我的sql查询最近7天的数据?如果数据不在那里，那么甚至获取日期，并显示为0或null

Question

我用sql Fidldle做了一个演示。我的表有以下列

displayId | displaytime | campaignId

现在我想要的是为特定的campaignId (我的意思是campaignId="")选择最近7天的条目，应该有多个条目具有相同的活动id..so，我想要显示它们的日期的总campaignId总和

因此，如果有7条日期为2013-3-8和其他日期的记录，则会显示如下记录

2013-03-02 | 1
2013-03-03 | 1
2013-03-04 | 0
2013-03-05 | 0
2013-03-06 | 0
2013-03-07 | 2
2013-03-08 | 7

在下面的查询中，它只显示了计数超过0的日期。例如，我尝试的是作为follows..but，它只给我一条在数据库中有条目的记录……

 2013-03-08 | 7


SELECT date(a.displayTime) AS `DisplayTime`,
       ifnull(l.TCount,0) AS TCount
FROM a_ad_display AS a
INNER JOIN
  (SELECT count(campaignId) AS TCount,
          displayTime
   FROM a_ad_display
   WHERE CONVERT_TZ(displaytime,'+00:00','-11:00') >= DATE_SUB(CONVERT_TZ(CURDATE(),'+00:00','-11:00') ,INTERVAL 1 DAY)
     AND CONVERT_TZ(displaytime,'+00:00','-11:00') <= CONVERT_TZ(CURDATE(),'+00:00','-11:00')
     AND campaignId = 20747
   GROUP BY DATE(displayTime)) AS l ON date(a.displayTime) = date(l.displayTime)
GROUP BY DATE(a.displayTime)
ORDER BY a.displaytime DESC LIMIT 7

我已经在我的查询中实现了时区，所以如果您可以帮助我处理这个简单的查询，那么它的ok..dont包含Convert_Tz行。

这是我的虚拟实体的http://sqlfiddle.com/#!2/96600c/1链接

Answer 1

如果您使用dates表，您的查询可以像下面这样简单：

select dates.fulldate, count(a_ad_display.id)
from dates
left outer join a_ad_display ON dates.fulldate = a_ad_display.displaytime
    [AND <other conditions here>]
where dates.fulldate BETWEEN date_add(curdate(), interval -6 day) AND curdate()
group by dates.fulldate

http://sqlfiddle.com/#!2/51e17/3

在不使用dates表的情况下，有一种方法。它很难看，可能对性能也很糟糕：

select displaytime, sum(c)
from
(
  select displaytime, count(a_ad_display.id) AS c
  from a_ad_display
  where displaytime BETWEEN date_add(curdate(), interval -6 day) AND curdate()
  group by displaytime
  union all
  select curdate(), 0
  union all
  select date_add(curdate(), interval -1 day), 0
  union all
  select date_add(curdate(), interval -2 day), 0
  union all
  select date_add(curdate(), interval -3 day), 0
  union all
  select date_add(curdate(), interval -4 day), 0
  union all
  select date_add(curdate(), interval -5 day), 0
  union all
  select date_add(curdate(), interval -6 day), 0
) x
group by displaytime
order by displaytime

http://sqlfiddle.com/#!2/96600c/16

Answer 2

很简单！你可以用PHP来完成。首先创建日期数组，如下所示

date = date('Y-m-d'); $date1 = date('Y-m-d', strtotime('-1 days')); $date2 = date('Y-m-d', strtotime('-2 days'));$date3 = date('Y-m-d', strtotime('-3 days'));$date4 = date('Y-m-d', strtotime('-4 days'));$date5 = date('Y-m-d', strtotime('-5 days'));$date6 = date('Y-m-d', strtotime('-6 days')); 
                $dt_arr = array($date6,$date5,$date4,$date3,$date2,$date1,$date);

从今天开始的最后7天，使用foreach并在foreach中运行带有where date字段的查询，如下所示

 foreach ($dt_arr as $value) 
    {
     $qry = mysqli_fetch_array(mysqli_query($link,"select * from table where dt_field = $value"));
       if($qry['value'] == '')
         {
           $valfield = 0;
          $dtfiled = $value;

     }