我正在使用MySQl在一个“模块”表中的类别ID的基础上从一个表中的类别名称。
我有下面的SQL可以很好地满足我的需求,但我想知道这是否被认为是一个JOIN?
因为它不调用JOIN?
SELECT `mo_category_fk` , `mo_name_vc` , `mc_name_vc`
FROM x_modcats mc, x_modules m
WHERE mc.mc_id_pk = m.mo_category_fk
AND m.mo_folder_vc = :module发布于 2013-03-17 09:08:54
是的,你加入了。根据documentation,,可以用作JOIN关键字的替代品。除非您不能使用非常有用的ON子句。但是,在WHERE子句中有一个连接表的条件。在我看来,将其作为FROM子句的一部分更有意义:
SELECT mo_category_fk, mo_name_vc, mc_name_vc
FROM x_modcats mc
JOIN x_modules m ON (mc.mc_id_pk = m.mo_category_fk)
WHERE m.mo_folder_vc = :module发布于 2013-03-17 09:09:01
是-在MySQL中,隐式连接和显式连接具有相同的执行计划。您可以使用EXPLAIN验证这一点。但这里有一个来自另一个线程的示例:
mysql> explain select * from table1 a inner join table2 b on a.pid = b.pid;
+----+-------------+-------+------+---------------+------+---------+--------------+------+-------+
| id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra |
+----+-------------+-------+------+---------------+------+---------+--------------+------+-------+
| 1 | SIMPLE | b | ALL | PRIMARY | NULL | NULL | NULL | 986 | |
| 1 | SIMPLE | a | ref | pid | pid | 4 | schema.b.pid | 70 | |
+----+-------------+-------+------+---------------+------+---------+--------------+------+-------+
2 rows in set (0.02 sec)
mysql> explain select * from table1 a, table2 b where a.pid = b.pid;
+----+-------------+-------+------+---------------+------+---------+--------------+------+-------+
| id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra |
+----+-------------+-------+------+---------------+------+---------+--------------+------+-------+
| 1 | SIMPLE | b | ALL | PRIMARY | NULL | NULL | NULL | 986 | |
| 1 | SIMPLE | a | ref | pid | pid | 4 | schema.b.pid | 70 | |
+----+-------------+-------+------+---------------+------+---------+--------------+------+-------+
2 rows in set (0.00 sec)https://stackoverflow.com/questions/15456537
复制相似问题