Arduino Serial.println

Question

#include <SoftwareSerial.h>

int blueTx = 2;
int blueRx = 3;

SoftwareSerial mySerial(blueTx, blueRx);

String myString = "";

void setup() {
  Serial.begin(9600);
  mySerial.begin(9600);


}

void loop() {
  while (mySerial.available()){
    char myChar = (char)mySerial.read();
    myString += myChar;
    delay(5);
}

  if (!myString.equals("")){
    Serial.println("input value : " + myString);    //this is error area 
    myString = "";
  }
}

我找不到这是错误为什么我知道“串行”不应该使用着色器文件为什么Serial.println有错误我键入Serial.begin....

Answer 1

最后几个代码需要更正，详细说明如下：

if (!myString.equals("")){
   String str = "Input value : ";
   str += myString;
   Serial.println(str);    
   myString = "";
}