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是否可以将boost累加器用作类成员
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Stack Overflow用户
提问于 2013-03-06 09:02:48
回答 1查看 1.7K关注 0票数 3

我正在尝试使用一个提升累加器来计算滚动平均值。当我像这样声明内联变量时:

代码语言:javascript
复制
#include <iostream>
#include <boost/accumulators/accumulators.hpp>
#include <boost/accumulators/statistics/stats.hpp>
#include <boost/accumulators/statistics/rolling_mean.hpp>

using namespace boost::accumulators;

int main()
{
  // Define rolling_mean accumulator
  accumulator_set<double, stats<tag::rolling_mean > > acc(tag::rolling_window::window_size = 5);
    // push in some data ...
    acc(1.2);
    acc(2.3);
    acc(3.4);
    acc(4.5);

    // Display the results ...
    std::cout << "Mean:   " << rolling_mean(acc) << std::endl;

    return 0;
}

它工作得很好。当我像这样将累加器声明为类的成员时:

代码语言:javascript
复制
#include <iostream>
#include <boost/accumulators/accumulators.hpp>
#include <boost/accumulators/statistics/stats.hpp>
#include <boost/accumulators/statistics/rolling_mean.hpp>

using namespace boost::accumulators;

class DoMean {
private:
  accumulator_set<double, stats<tag::rolling_mean > > m_acc(tag::rolling_window::window_size = 5);

public:

  void addData(double val) {
    this->m_acc(val);
  }

  double getMean(void) {
    return rolling_mean(this->m_acc);
  }
};

int main()
{
  // Define an accumulator set for calculating the mean and the
  // 2nd moment ...
  DoMean meaner;
  meaner.addData(1.2);
  meaner.addData(2.3);
  meaner.addData(3.4);
  meaner.addData(4.5);

  // push in some data ...

  // Display the results ...
  std::cout << "Mean:   " << meaner.getMean() << std::endl;

  return 0;
}

它会失败,给编译器带来错误:

代码语言:javascript
复制
accumulators::tag::rolling_window::window_size is not a type
...blah blah, many type template errors etc.
EN

回答 1

Stack Overflow用户

回答已采纳

发布于 2013-03-06 09:02:48

这个问题的正确解决方案是:

代码语言:javascript
复制
#include <iostream>
#include <boost/accumulators/accumulators.hpp>
#include <boost/accumulators/statistics/stats.hpp>
#include <boost/accumulators/statistics/rolling_mean.hpp>

using namespace boost::accumulators;

class DoMean {
private:
  accumulator_set<double, stats<tag::rolling_mean > > m_acc;

public:

  DoMean(void): m_acc(tag::rolling_window::window_size = 5) {}

  void addData(double val) {
    this->m_acc(val);
  }

  double getMean(void) {
    return rolling_mean(this->m_acc);
  }
};

int main()
{
  // Define an accumulator set for calculating the mean and the
  // 2nd moment ...
  DoMean meaner;
  meaner.addData(1.2);
  meaner.addData(2.3);
  meaner.addData(3.4);
  meaner.addData(4.5);

  // push in some data ...

  // Display the results ...
  std::cout << "Mean:   " << meaner.getMean() << std::endl;

  return 0;
}

请注意,m_acc的初始化已经从内联声明移到了初始化列表中。这解决了所有的编译器错误。事实上,如果我们考虑一下这里发生的事情,最初尝试在类中使用累加器失败的原因是因为ISO c++禁止内联成员的初始化。

我们可以用另一个简单的类来演示:

代码语言:javascript
复制
#include <iostream>

class TestInit {
public:
  int m_init = 10;

};

int main() {
  TestInit inits;
  std::cout << "The value: " << inits.m_init << std::endl;

}

现在编译器给了我们一个有用的消息:

代码语言:javascript
复制
/home/me/prog/cpp/acctest/testinit.cxx:5:16: error: ISO C++ forbids initialization of member m_init [-fpermissive]
/home/me/prog/cpp/acctest/testinit.cxx:5:16: error: making m_init static [-fpermissive]
/home/me/prog/cpp/acctest/testinit.cxx:5:16: error: ISO C++ forbids in-class initialization of non-const static member m_init
票数 8
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/15237135

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