在MULE 3.3.0 CE中,我用构造函数和两个方法编写了一个简单的java类,我将它们复制到下面:
public class Book {
private String title;
public Book(String theTitle) {
// TODO Auto-generated constructor stub
title = theTitle;
}
public String getTitle(){
return title;
}
public String displayAuthorName(String authorName) {
return authorName;
}
}现在,我想添加java类,作为.mflow(Configuration XML)中的bean,然后将有效负载传递给java类方法。
我该如何解决这个问题?
发布于 2013-03-04 08:06:42
为了完成此任务,您需要:
下面是一个示例:
package com.mypackage.test;
import org.mule.api.annotations.param.Payload;
public class MyComponent {
private String myProperty;
public String getMyProperty() {
return myProperty;
}
public void setMyProperty(String myProperty) {
this.myProperty = myProperty;
}
public String doProcess(@Payload String payload) {
//do something interesting
return "You said: " + payload;
}
}定义入口点的一种方法是使用@Payload注释。
然后是一个示例流程:
<spring:bean id="myBean" class="com.mypackage.test.MyComponent">
<spring:property name="myProperty" value="Some Value" />
</spring:bean>
<flow name="componentFlow">
<http:inbound-endpoint address="http://localhost:8082/test" />
<component>
<spring-object bean="myBean" />
</component>
<set-property propertyName="Content-Type" value="text/plain" doc:name="Property" />
</flow>https://stackoverflow.com/questions/15184806
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