在下面的代码中,我想包括结构的第三个维度。结构基因型和其余标识符已经定义。这是没有问题的:
struct genotype ** populationrows = (struct genotype **) calloc(MAXGENS, sizeof(struct genotype *));
for (k=0; k< MAXGENS; k++) {
populationrows[k]= (struct genotype *) calloc (POPSIZE, sizeof (struct genotype));
for (j=0; j<2; j++) {
for (i=0; i<3; i++) {
populationrows[k][j].fitness = 0;
populationrows[k][j].rfitness = 0;
populationrows[k][j].cfitness = 0;
populationrows[k][j].lower[i] = 1.0;
populationrows[k][j].upper[i]= 2.0;
populationrows[k][j].gene[i] = 3.0;
printf(" populationrows[%u][%u].gene[%u]=%25lf \n", k,j,i,populationrows[k][j].gene[i]);
}
}
}对于第三个维度,我尝试了以下方法:
结构基因型*人口行=(结构基因型*) calloc(numFiles,sizeof(结构基因型* *) );
对于(w=0;w< numFiles;w++){
populationrowsw= (结构基因型**) calloc (MAXGENS,sizeof (结构基因型*));
for (k=0; k<MAXGENS; k++) {
for (j=0; j<2; j++) {
for (i=0; i<3; i++) {
populationrows[w][k][j].fitness = 0;
populationrows[w][k][j].rfitness = 0;
populationrows[w][k][j].cfitness = 0;
populationrows[w][k][j].lower[i] = 1.0;
populationrows[w][k][j].upper[i]= 2.0;
populationrows[w][k][j].gene[i] = 3.0;
printf(" populationrows[%u][%u][%u].gene[%u]=%25lf \n", w,k,j,i,populationrows[w][k][j].gene[i]);
}
}
}
}但这给了我一个分割错误。
您介意告诉我如何避免这种分割错误吗?任何帮助都将不胜感激。
提前感谢您的回复!
发布于 2013-02-17 18:58:19
我假设它是C。
与指向数据指针的指针数组相比,使用平面数组更好。大概是这样的:
int n_w = 42, n_k = 23, n_j = 423; // size of dimensions
struct genotype * population = (struct genotype *) calloc(n_w * n_k * n_j, sizeof(struct genotype));您将获得元素(10,11,12),然后使用:
population[10 * n_k * n_j + 11 * n_j + 12].fitness = 0;如果你把它放到函数中,它会变得很漂亮:
int n_w = 42, n_k = 23, n_j = 423; // size of dimensions
struct genotype * create_array() {
return (struct genotype *) calloc(n_w * n_k * n_j, sizeof(struct genotype));
}
struct genotype * get_element(int w, int k, int j) {
return &population[w * n_k * n_j + k * n_j + j];
}
// ...
struct genotype * population = create_array();
get_element(10, 11, 12)->fitness = 0;https://stackoverflow.com/questions/14920105
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