OleDB插入命令错误

Question

OleDbConnection con = new OleDbConnection(@" provider=Microsoft.ace.Oledb.12.0; data source=\\sisc-erelim\4_Printing\VTDB\DB\VirginiTEADB2.accdb; Persist Security Info=False");

private void button1_Click(object sender, EventArgs e)
        {
            try
            {
                OleDbCommand cmd = new OleDbCommand();
                cmd.CommandType = CommandType.Text;
                cmd.CommandText = "INSERT INTO Accountstbl (Username, Password)" + "VALUES ('" + textBox1.Text + "','" + textBox2.Text + "')";
                cmd.Parameters.AddWithValue("@Username", textBox1.Text);
                cmd.Parameters.AddWithValue("@Password", textBox2.Text);
                cmd.Connection = con;
                con.Open();
                cmd.ExecuteNonQuery();
            }
            catch (Exception ex)
            {
                textBox1.Text = ex.ToString();
            }

我总是会遇到这样的错误，

System.Data.OleDb.OleDbException: Syntax error in INSERT INTO statement.
   at System.Data.OleDb.OleDbCommand.ExecuteCommandTextErrorHandling(OleDbHResult hr)
   at System.Data.OleDb.OleDbCommand.ExecuteCommandTextForSingleResult(tagDBPARAMS dbParams, Object& executeResult)
   at System.Data.OleDb.OleDbCommand.ExecuteCommandText(Object& executeResult)
   at System.Data.OleDb.OleDbCommand.ExecuteCommand(CommandBehavior behavior, Object& executeResult)
   at System.Data.OleDb.OleDbCommand.ExecuteReaderInternal(CommandBehavior behavior, String method)
   at System.Data.OleDb.OleDbCommand.ExecuteNonQuery()
   at VirginiTEAcorp.Form3.button1_Click(Object sender, EventArgs e) in C:\Documents and Settings\12-014s\My Documents\applications\Database\WindowsFormsApplication1\Form3.cs:line 34

Answer 1

您定义了@Username和@Password参数，但从未在sql命令中使用过。

怎么样?

cmd.CommandText = "INSERT INTO Accountstbl (Username, [Password]) VALUES (@Username, @Password)";
cmd.Parameters.AddWithValue("@Username", textBox1.Text);
cmd.Parameters.AddWithValue("@Password", textBox2.Text);
cmd.Connection = con;
con.Open();
cmd.ExecuteNonQuery();

此外，您应该在sql命令中使用Password，如[Password]，因为它是MS Access中的。

如果您不这样做，这可能会导致错误，如；

密码关键字“

”

附近的语法不正确

Answer 2

试着改变这种方式

 cmd.CommandText = "INSERT INTO Accountstbl (Username, Password) VALUES (@Username,@Password)";

Answer 3

insert语句中需要一个空格：

ssword)" + "VALUES ('" 

例如，在您的语句中，您进行了连接，而不允许使用空格。

应该是：

ssword)" + " VALUES ('" 

例如。