当我执行以下代码时,所附图像中以黄色突出显示的查询将在页面中打印出来。我不想打印那个sql。我的代码段出了什么问题?

if(isset($_REQUEST["stu_performance_activity_submit"]))
{
$stu_performance_main_category = $_REQUEST["stu_performance_main_category"];
$stu_performance_sub_category = $_REQUEST["stu_performance_sub_category"];
$stu_performance_activity_name = $_REQUEST["stu_performance_activity_name"];
$stu_performance_activity_date = $_REQUEST["stu_performance_activity_date"];
$stu_performance_activity_description = $_REQUEST["stu_performance_activity_description"];
$newc = "INSERT INTO stu_performance_activity
(stu_performance_activity_id,
stu_performance_main_category,
stu_performance_sub_category,
stu_performance_activity_name,
stu_performance_activity_date,
stu_performance_activity_description)
VALUES ('',
'$stu_performance_main_category',
'$stu_performance_sub_category',
'$stu_performance_activity_name',
'$stu_performance_activity_date',
'$stu_performance_activity_description')";
if($connection->query($newc) === TRUE)
{
}
else
{
echo "Error: " . $newc . "<br>" . $connection->error;
}
}发布于 2016-08-30 03:09:38
插入过程中主键应为NULL。以如下方式重写您的查询
$newc = "INSERT INTO stu_performance_activity
(stu_performance_activity_id,
stu_performance_main_category,
stu_performance_sub_category,
stu_performance_activity_name,
stu_performance_activity_date,
stu_performance_activity_description)
VALUES (NULL,
'$stu_performance_main_category',
'$stu_performance_sub_category',
'$stu_performance_activity_name',
'$stu_performance_activity_date',
'$stu_performance_activity_description')";https://stackoverflow.com/questions/39213377
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