我有下面显示的表格。我正在使用它作为我的android测验应用程序。我想去接那些不能参加测验的学生。
表格测验
+-------------------------------------------------------------------+
| id | title | start | end | class_name | user_faculty |
+-------------------------------------------------------------------+
| 1 | Quiz 1 | 2016-08-01 | 2016-08-03 | T4 | faculty_1 |
+-------------------------------------------------------------------+
| 2 | Quiz 2 | 2016-08-01 | 2016-08-03 | T4 | faculty_1 |
+-------------------------------------------------------------------+
| 3 | Quiz 3 | 2016-08-03 | 2016-08-04 | T4 | faculty_1 |
+-------------------------------------------------------------------+表学生班
+-----------------------------------------------+
| id | class_name | user_faculty | user_student |
+-----------------------------------------------+
| 1 | T4 | faculty_1 | student_1 |
+-----------------------------------------------+
| 2 | T4 | faculty_1 | student_2 |
+-----------------------------------------------+我在这里的初始查询是:
SELECT Q.id, Q.title, Q.start, Q.end
FROM quiz Q
INNER JOIN studentclass SC
ON Q.class_name = SC.class_name
AND Q.start_on <= now()
AND Q.end_on >= now()
AND SC.user_student = 'student_1'假设今天的日期是2016-08-02
我能够获取测验表的第一行和第二行
+---------------------------------------+
| id | title | start | end |
+---------------------------------------+
| 1 | Quiz 1 | 2016-08-01 | 2016-08-03 |
+---------------------------------------+
| 2 | Quiz 2 | 2016-08-01 | 2016-08-03 |
+---------------------------------------+现在,我还想获取分数表以及前面的查询。一个叫“student_1”的学生完成了测验。
表分数
+--------------------------------------------------------+
| id | score | grade | user_student | quiz_id | status |
+--------------------------------------------------------+
| 1 | 10 | 100 | student_1 | 1 | Finished |
+--------------------------------------------------------+我的新查询
SELECT Q.id, Q.title, Q.start, Q.end, S.user_student, S.status
FROM quiz Q
INNER JOIN studentclass SC
ON Q.class_name = SC.class_name
AND Q.start_on <= now()
AND Q.end_on >= now()
AND SC.user_student = 'student_1'
LEFT JOIN score S
ON Q.id = S.quiz_id
WHERE S.quiz_id IS NULL结果是
+---------------------------------------------------------------+
| id | title | start | end | user_student | status |
+---------------------------------------------------------------+
| 2 | Quiz 2 | 2016-08-01 | 2016-08-03 | NULL | NULL |
+---------------------------------------------------------------+结果很好,但当我在第二个查询中将student_1更改为student_2时,我仍然得到相同的结果。student_2应该会看到两个测验行,因为他还没有参加测验。
SELECT Q.id, Q.title, Q.start, Q.end, S.user_student, S.status
FROM quiz Q
INNER JOIN studentclass SC
ON Q.class_name = SC.class_name
AND Q.start_on <= now()
AND Q.end_on >= now()
AND SC.user_student = 'student_2' //this is where I changed the student_1 to student_2
LEFT JOIN score S
ON Q.id = S.quiz_id
WHERE S.quiz_id IS NULL感谢您的回答
发布于 2016-08-12 05:07:48
问题似乎是,当加入SCORE表时,您没有检查哪个学生参加了测验。因此,如果测验是由任何学生完成的,则测验将从结果中排除。
尝试更改查询,如下所示:
SELECT Q.id, Q.title, Q.start, Q.end, S.user_student, S.status
FROM quiz Q
INNER JOIN studentclass SC
ON Q.class_name = SC.class_name
AND Q.start_on <= now()
AND Q.end_on >= now()
LEFT JOIN score S
ON Q.id = S.quiz_id
AND SC.user_student = S.user_student -- Do not consider other students
WHERE S.quiz_id IS NULL
AND SC.user_student = 'student_2' -- moved from join clause for clarityhttps://stackoverflow.com/questions/38903975
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