按块读取文件，而不是逐行读取文件？

Question

我有一个文本文件，如下所示：

[1] Header information Timestamp Text begins
Text continues
Text continues
Text continues

[2] Header information Timestamp Text begins
Text continues
Text continues

[3] Header information Timestamp Text begins
Text continues
Text continues
Text continues

我希望读取该文件，并单独处理每个条目(它们的行数在1到20或30行之间)。

有没有办法使用空行作为分隔符来遍历文件？

Answer 1

答案是肯定的！

awk -vRS="" '...'会将空行视为行拆分器。

以您的示例为例，测试：

kent$  cat b.txt
[1] Header information Timestamp Text begins
Text continues
Text continues
Text continues

[2] Header information Timestamp Text begins
Text continues
Text continues

[3] Header information Timestamp Text begins
Text continues
Text continues
Text continues

kent$  awk -vRS="" '{print "==== new block here ===="}1' b.txt  
==== new block here ====
[1] Header information Timestamp Text begins
Text continues
Text continues
Text continues
==== new block here ====
[2] Header information Timestamp Text begins
Text continues
Text continues
==== new block here ====
[3] Header information Timestamp Text begins
Text continues
Text continues
Text continues

Answer 2

这是一个纯bash解决方案：

{
    read -r block    # First line only
    while read -r; do
        if [[ $REPLY =~ ^$ ]]; then
            # Do what you like with the contents 
            # $block here, then ...
            block=""
        else
            block+="$REPLY"
        fi
    done
 } < file.txt