PHP可捕获致命错误

Question

我正在尝试用wsdl2php在PHP中处理web服务，但做不到。生成的web服务客户端代码，结果为：

class CreateProfile {

  public $firstname;
  public $email;
  public $lastname;
  public $mobile;
  public $password;
  public $provider;
  public $uniqueID;
  public $username;
}

class CreateProfileResponse {

  public $CreateProfileResult;
}

class Profile_WebService extends SoapClient {

  private static $classmap = array(

  'CreateProfile' => 'CreateProfile',
  'CreateProfileResponse' => 'CreateProfileResponse',
);

public function Profile_WebService($wsdl = "http://domain/wcfservice/Profile.WebService.asmx?WSDL", $options = array()) {
foreach(self::$classmap as $key => $value) {
  if(!isset($options['classmap'][$key])) {
    $options['classmap'][$key] = $value;
  }
}
parent::__construct($wsdl, $options);
}


public function CreateProfile(CreateProfile $parameters) {
  return $this->__soapCall('CreateProfile', array($parameters),       array(
          'uri' => 'http://domain/',
          'soapaction' => ''
         )
     );
  }

}

我想这样使用它：

$client = new Profile_WebService();
$client->CreateProfile(array('provider' => 'ENERGIZER','username' => 'ENGtest1','password' => '1369','uniqueId' => '102030405062'));

但它一直在说：

PHP Catchable fatal error:  Argument 1 passed to Profile_WebService::CreateProfile() must be an instance of CreateProfile, array given, called.

你能给我讲讲吗？

Answer 1

创建一个新的CreateProfile类实例：

$createProfile = new CreateProfile();

将vars分配给它：

$createProfile->firstname = 'Fred';
$createProfile->email = 'test@example.com';
...
...

然后将该对象传递到您的方法中：

$client = new Profile_WebService();
$client->CreateProfile($createProfile);

Answer 2

CreateProfile需要一个对象，而不是数组。所以这就是：

$client = new Profile_WebService();
$client->CreateProfile(array('provider' => 'ENERGIZER','username' => 'ENGtest1','password' => '1369','uniqueId' => '102030405062'));

可以快速切换到以下内容：

$client = new Profile_WebService();
$CreateProfile_array = array('provider' => 'ENERGIZER','username' => 'ENGtest1','password' => '1369','uniqueId' => '102030405062');
$CreateProfile_object = (object)$CreateProfile_array;
$client->CreateProfile($CreateProfile_object);

Answer 3

您告诉PHP在CreateProfile类型的函数CreateProfile() 1参数中。

但是在这行$client->CreateProfile(array('provider' => 'ENERGIZER','username' => 'ENGtest1','password' => '1369','uniqueId' => '102030405062'));中，您传递的是一个数组类型的变量。

您必须将该数组类型转换为object类型，如下所示：

$client->CreateProfile((object) array('provider' => 'ENERGIZER','username' => 'ENGtest1','password' => '1369','uniqueId' => '102030405062'));