<hr class="calibre2" />
<h3 class="calibre5">-ability</h3> (in nouns 构成名词) : <br class="calibre4" />
<blockquote class="calibre6"><p class="calibre_1"><span class="italic">◊ capability 能力 </span></p></blockquote>
<blockquote class="calibre6"><p class="calibre_1"><span class="italic">◊ responsibility 责任 </span></p></blockquote>
<hr class="calibre2" />
<h3 class="calibre5">-ibility</h3> (in nouns 构成名词) : <br class="calibre4" />
<blockquote class="calibre6"><p class="calibre_1"><span class="italic">◊ capability 能力 </span></p></blockquote>
<blockquote class="calibre6"><p class="calibre_1"><span class="italic">◊ responsibility 责任 </span></p></blockquote>
<hr class="calibre2" />上面这是我的汤的一部分,我想在两个<hr>之间获得内容,因为hr不是一个结束标记,所以我不能使用一些简单的方法,我想如果我可以使用find_next_elements,但如何能让他停下来,当他看到<hr class = 'calibre2'>,这样我就可以获得那些内容,谢谢。
发布于 2016-07-31 12:03:09
您可以遍历所有hr元素,并使用.find_next_siblings()遍历下一个同级元素。然后,如果你遇到了hr,打破这个循环:
for hr in soup.find_all("hr", class_="calibre2"):
for item in hr.find_next_siblings():
if item.name == "hr":
break
print(item)
print("-----")发布于 2016-07-31 13:41:36
您可以结合find_all_next https://www.crummy.com/software/BeautifulSoup/bs4/doc/#find-all-next-and-find-next检查hr和calibre2类
from bs4 import BeautifulSoup
testStr = """
<hr class="calibre2" />
<h3 class="calibre5">-ability</h3> (in nouns 构成名词) : <br class="calibre4" />
<blockquote class="calibre6"><p class="calibre_1"><span class="italic">◊ capability 能力 </span></p></blockquote>
<blockquote class="calibre6"><p class="calibre_1"><span class="italic">◊ responsibility 责任 </span></p></blockquote>
<hr class="calibre2" />
<h3 class="calibre5">-ibility</h3> (in nouns 构成名词) : <br class="calibre4" />
<blockquote class="calibre6"><p class="calibre_1"><span class="italic">◊ capability 能力 </span></p></blockquote>
<blockquote class="calibre6"><p class="calibre_1"><span class="italic">◊ responsibility 责任 </span></p></blockquote>
<hr class="calibre2" />
""";
soup = BeautifulSoup(testStr, 'lxml')
hrTag = soup.hr
nextTags = hrTag.find_all_next()
content = []
for item in nextTags:
# check if we have reached the second calibre2 hr
print("Name %s ; Class %s" % (item.name, item['class'][0]))
if item.name == 'hr' and item['class'][0] == 'calibre2':
break
content.append(item)
print(content)https://stackoverflow.com/questions/38680626
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