我有几千个对少数因素的观察,根据每个因素的最小值,我将其转换为离散的1/0值,并将其绘制在热图中。2 (red=1,black=0)。这将绘制A+B+C+D为1的组合,3个因素的组合为1,2个因素的组合,等等。我希望在热图中的左侧垂直轴上绘制这些组合的分数。2:
nentries=10000
ci=rainbow(nentries)
set.seed=1
mean=10
## Generate some data (4 factors)
i = data.frame(
a=round(abs(rnorm(nentries,mean-2))),
b=round(abs(rnorm(nentries,mean-1))),
c=round(abs(rnorm(nentries,mean+1))),
d=round(abs(rnorm(nentries,mean+2)))
)
minvalue = 10
# Discretise values to 1 or 0
m0 = matrix(as.numeric(i>minvalue),nrow=nrow(i))
# Remove rows with all zeros
m = m0[rowSums(m0)>0,]
# Reorder with 1,1,1,1 on top
ms =m[order(as.vector(m %*% matrix(2^((ncol(m)-1):0),ncol=1)), decreasing=TRUE),]
rowci = rainbow(nrow(ms))
colci = rainbow(ncol(ms))
heatmap(ms,
Rowv=NA,
labRow=" ",
keep.dendro = FALSE,
col=c("black","red"),
RowSideColors=rowci,
ColSideColors=colci,
)RowSideColors现在是一个彩虹,有和nrow(ms)一样多的颜色,我想要的是1/0组合的因子和一个图例。类似于:A+B+C+D 1%、B+C+D 10%等,在RowSideColors旁边。有什么想法吗?
发布于 2013-01-17 22:25:50
如果我没理解错的话,您想要少量的行标签,每个块一个?这应该能起到作用
colnames(ms)=LETTERS[1:4]
limits=c(which(!duplicated(ms)),nrow(ms))
l=length(limits)
toname=round((limits[-l]+ limits[-1])/2)
freq=(limits[-1]-limits[-l])/nrow(ms)
rn=rep("", nrow(ms))
for(i in toname) rn[i]=paste(colnames(ms)[which(ms[i,]==1)],collapse="")
rn[toname]=paste(rn[toname], ": ", sprintf( "%.5f", freq ), "%")
heatmap(ms, Rowv=NA, labRow=rn, col=c("black","red"))它利用您的数据已经排序的事实来找到每个块的中间(我们希望图例出现的位置),然后创建一个图例矢量,该矢量对于大多数行都是空的,并包含列名和图例应该显示的行的比例。
https://stackoverflow.com/questions/14243723
复制相似问题