如何以编程方式在另一个ShapeDrawable中绘制较小的shapeDrawable

Question

我正试着在另一个圆内画一个更小的圆。这看起来很简单，但我在这方面遇到了麻烦，找不到答案。im使用的代码是：

    ShapeDrawable biggerCircle= new ShapeDrawable( new OvalShape());
    biggerCircle.setIntrinsicHeight( 60 );
    biggerCircle.setIntrinsicWidth( 60);
    biggerCircle.setBounds(new Rect(0, 0, 60, 60));
    biggerCircle.getPaint().setColor(Color.BLUE);

    ShapeDrawable smallerCircle= new ShapeDrawable( new OvalShape());
    smallerCircle.setIntrinsicHeight( 10 );
    smallerCircle.setIntrinsicWidth( 10);
    smallerCircle.setBounds(new Rect(0, 0, 10, 10));
    smallerCircle.getPaint().setColor(Color.BLACK);
    smallerCircle.setPadding(50,50,50,50);

    LayerDrawable composite1 = new LayerDrawable(new Drawable[] biggerCircle,smallerCircle,});

但这并不管用，发生的情况是小圆圈变得和大圆圈一样大。因此，唯一显示的是带有biggerCircle大小的黑色圆圈。如果有人能帮上忙，我将不胜感激。提前谢谢。

Answer 1

改变顺序，

Drawable[] d = {smallerCircle,biggerCircle};

LayerDrawable composite1 = new LayerDrawable(d);

试着这样做

        ShapeDrawable biggerCircle= new ShapeDrawable( new OvalShape());
        biggerCircle.setIntrinsicHeight( 60 );
        biggerCircle.setIntrinsicWidth( 60);
        biggerCircle.setBounds(new Rect(0, 0, 60, 60));
        biggerCircle.getPaint().setColor(Color.BLUE);

        ShapeDrawable smallerCircle= new ShapeDrawable( new OvalShape());
        smallerCircle.setIntrinsicHeight( 10 );
        smallerCircle.setIntrinsicWidth( 10);
        smallerCircle.setBounds(new Rect(0, 0, 10, 10));
        smallerCircle.getPaint().setColor(Color.BLACK);
        smallerCircle.setPadding(50,50,50,50);
        Drawable[] d = {smallerCircle,biggerCircle};

        LayerDrawable composite1 = new LayerDrawable(d);

        btn.setBackgroundDrawable(composite1);  

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