我想不出该怎么做:
我有:
icon-braille icon-bookmark-empty icon-blogger icon-adult icon-address-book
我想要:
'icon-braille','icon-bookmark-empty','icon-blogger','icon-adult','icon-address-book'
发布于 2013-01-03 21:13:27
这是OSX友好的sed "s/ /','/g;s/^/'/;s/$/'/"
$ echo "icon-braille icon-bookmark-empty" | sed "s/ /','/g;s/^/'/;s/$/'/"
'icon-braille','icon-bookmark-empty'发布于 2013-01-03 21:11:10
使用shell和sed:
echo "'"$(sed "s/ /','/g")"'"示例:
$ echo "'"$(sed "s/ /','/g")"'"
icon-braille icon-bookmark-empty icon-blogger icon-adult icon-address-book
'icon-braille','icon-bookmark-empty','icon-blogger','icon-adult','icon-address-book'第一行被插入,第二行被生成。
发布于 2013-01-03 21:14:13
$ echo "icon-braille icon-bookmark-empty icon-blogger icon-adult icon-address-book" | sed -e "s/ \+/','/g" -e "s/^/'/" -e "s/$/'/"
'icon-braille','icon-bookmark-empty','icon-blogger','icon-adult','icon-address-book'https://stackoverflow.com/questions/14139527
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