下面是一些示例信息:
ROW | PHONE | ID | NAME
_________________________________________
1 000-000-0000 3 Company1
2 000-000-0000 38 Company2
1 123-456-7890 0 Company3
2 123-456-7890 0 Company4
3 123-456-7890 0 Company5
1 197-865-4329 0 Company6
2 197-865-4329 18 Company7
1 654-987-1230 74 Company8
2 654-987-1230 2 Company9
1 951-753-8462 2 Company10
2 951-753-8462 3 Company11
3 951-753-8462 3 Company12
4 951-753-8462 3 Company13此信息是使用以下代码从表中提取的:
USE MyTable
GO
SELECT ROW_NUMBER() OVER (PARTITION BY AI.telephone1 ORDER BY AI.telephone1) AS Row
,AI.telephone1 AS [Main Phone #]
,AI.new_id AS [ID]
,AI.name AS [Account Name]
,AI.emailaddress1 AS [Email Address]
,AI.contactname AS [Primary Contact]
FROM AccountsInfo AI
WHERE AI.telephone1 IN (
SELECT telephone1
FROM MyDatabase.dbo.AccountsInfo AI
WHERE telephone1 != 'NULL'
AND telephone1 != '--'
GROUP BY telephone1
HAVING COUNT(*) > 1
)
ORDER BY telephone1我现在需要做的是迭代每个分区,只提取具有匹配ID号的结果,但不能完全理解。下面是我想要的表格最后的样子。
PHONE | ID | NAME
_________________________________________
123-456-7890 0 Company3
123-456-7890 0 Company4
123-456-7890 0 Company5
951-753-8462 3 Company11
951-753-8462 3 Company12
951-753-8462 3 Company13如您所见,公司3、4和5都获得了结果,因为它们都有匹配的ID号和匹配的电话号码。公司11、12和13在他们的分区中找到了,因为他们有匹配的ID号。公司10未被删除,因为它的ID号与11、12和13不同。
我需要做的是让代码遍历每个分区(按电话号码划分),并检查分区中每行的ID号与分区中其他行的ID号。最终结果将是只有ID号在其分区内的其他位置重复的行。
如果你需要任何其他信息,请告诉我。
发布于 2012-12-20 23:53:03
这个怎么样?
SELECT AI.telephone1 AS [Main Phone #]
,AI.new_id AS [ID]
,AI.name AS [Account Name]
,AI.emailaddress1 AS [Email Address]
,AI.contactname AS [Primary Contact]
FROM AccountsInfo AI
INNER JOIN
(
SELECT telephone1,new_id
FROM MyDatabase.dbo.AccountsInfo AI
WHERE telephone1 != 'NULL'
AND telephone1 != '--'
GROUP BY telephone1, new_id
HAVING COUNT(*) > 1
) T
ON AI.telephone1 = T.telephone1
AND AI.new_id = T.new_id
ORDER BY AI.telephone1发布于 2012-12-23 00:40:51
您还可以使用having
select
"phone", "id"
from
"data"
group by "phone", "id"
having ( min ( "row" ) < max( "row" ));有关更多信息和可能性,请查看Joe Celko's Thinking in Sets
请参阅SQL-Fiddle
https://stackoverflow.com/questions/13975214
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