我的查询显示两个人的名字分别是"Anna“、"Szymkowiak”和这个相同的"id“,但这是同一个人。我该如何求和呢?例如:id "80","Anna","Szymkowiak"," 23 ",2 -> 23是20个月加3的和,2是Aneks 1加1的和
SELECT DISTINCT SBA.HRSystemId AS Id, SBA.FirstName, SBA.Surname,
CASE WHEN SBA.EndDate < GETDATE()
THEN DATEDIFF(MONTH,SBA.StartDate,SBA.EndDate)
ELSE DATEDIFF(MONTH,SBA.StartDate, GETDATE())
END AS Miesiace_Przepracowane,
MAX(SBC.ContractNumber) AS Aneks
FROM SB_Applications SBA JOIN SB_Contracts SBC ON SBA.ApplicationId = SBC.ApplicationId
WHERE SBA.IsActiveYN = 1 AND SBA.HRSystemId != 0 AND SBC.ApplicationStatusId = 4
GROUP BY SBA.FirstName, SBA.Surname,SBA.StartDate,SBA.EndDate,SBA.StartDate,SBA.HRSystemId,SBC.ContractNumber;我得到了这个:
id |FirstName|Surname|Miesiace_Przepracowane|Aneks
80, Anna, Szymkowiak, 20, 1
80, Anna, Szymkowiak, 3, 1
91, Jack, Sparrow, 2, 1
92, Tom, Jones, 1, 1
100, Rocky, Balboa, 3, 0这个例子不起作用

感谢同事的帮助,这对我来说是一次很好的训练:)我给你的帮助点数。
发布于 2012-12-11 18:07:35
当您已经有GROUP BY时,您几乎不想使用DISTINCT;它是无关的。
最自然、最快速的方法是使用派生表扩展查询:
SELECT HRSystemId, FirstName, SurName,
Sum(Miesiace_Przepracowane) Miesiace_Przepracowane,
MAX(Aneks) Aneks
FROM
(
SELECT SBA.HRSystemId AS Id, SBA.FirstName, SBA.Surname,
CASE WHEN SBA.EndDate < GETDATE()
THEN DATEDIFF(MONTH,SBA.StartDate,SBA.EndDate)
ELSE DATEDIFF(MONTH,SBA.StartDate, GETDATE())
END AS Miesiace_Przepracowane,
MAX(SBC.ContractNumber) AS Aneks
FROM SB_Applications SBA JOIN SB_Contracts SBC ON SBA.ApplicationId = SBC.ApplicationId
WHERE SBA.IsActiveYN = 1 AND SBA.HRSystemId != 0 AND SBC.ApplicationStatusId = 4
GROUP BY SBA.FirstName, SBA.Surname,SBA.StartDate,SBA.EndDate,SBA.StartDate,SBA.HRSystemId,SBC.ContractNumber
) X
GROUP BY HRSystemId, FirstName, SurName;发布于 2012-12-11 18:08:43
Select ID,FirstName,Surname,SUM(Miesiace_Przepracowane) as Miesiace_Przepracowane,SUM(Aneks) as Aneks from
(
SELECT DISTINCT SBA.HRSystemId AS Id, SBA.FirstName, SBA.Surname,
CASE WHEN SBA.EndDate < GETDATE()
THEN DATEDIFF(MONTH,SBA.StartDate,SBA.EndDate)
ELSE DATEDIFF(MONTH,SBA.StartDate, GETDATE())
END AS Miesiace_Przepracowane,
MAX(SBC.ContractNumber) AS Aneks
FROM SB_Applications SBA JOIN SB_Contracts SBC ON SBA.ApplicationId = SBC.ApplicationId
WHERE SBA.IsActiveYN = 1 AND SBA.HRSystemId != 0 AND SBC.ApplicationStatusId = 4
GROUP BY SBA.FirstName, SBA.Surname,SBA.StartDate,SBA.EndDate,SBA.StartDate,SBA.HRSystemId,SBC.ContractNumber;
) a
Group by ID,FirstName,Surname https://stackoverflow.com/questions/13817797
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