基本上,我想要完成的是使用编辑器redactor和函数imageGetJson从文件夹中获取上传图像的列表
我已经设法让fwrite在我的images.json文件中添加了一个数组。现在的问题是,redactor需要用括号括起输入,以便渲染图像。
因此,我的问题是如何获得数据周围的括号?
到目前为止,我上传的文件是:
// This is a simplified example, which doesn't cover security of uploaded images.
// This example just demonstrate the logic behind the process.
// files storage folder
$dir = '../img/uploads/';
$_FILES['file']['type'] = strtolower($_FILES['file']['type']);
if ($_FILES['file']['type'] == 'image/png'
|| $_FILES['file']['type'] == 'image/jpg'
|| $_FILES['file']['type'] == 'image/gif'
|| $_FILES['file']['type'] == 'image/jpeg'
|| $_FILES['file']['type'] == 'image/pjpeg')
{
// setting file's mysterious name
$filename = md5(date('YmdHis')).'.jpg';
$file = $dir.$filename;
// copying
copy($_FILES['file']['tmp_name'], $file);
// displaying file
$array = array(
'filelink' => '/img/uploads/'.$filename,
'thumb' => '/img/uploads/'.$filename,
'image' => '/img/uploads/'.$filename,
);
echo stripslashes(json_encode($array));
$json = stripslashes(json_encode($array)), "\n";
$files = fopen('../img/uploads/images.json','a+');
fwrite($files, $json . "\n");
fclose($files);
}我创建了一个包含文件位置的数组,并将其写入文件images.json
我需要它看起来像这样
[
{"filelink":"image.jpg","thumb":"image.jpg","image":"image.jpg"}
{"filelink":"image.jpg","thumb":"image.jpg","image":"image.jpg"}
{"filelink":"image.jpg","thumb":"image.jpg","image":"image.jpg"}
{"filelink":"image.jpg","thumb":"image.jpg","image":"image.jpg"}
]只是它添加了这样的内容:
[]
{"filelink":"image.jpg","thumb":"image.jpg","image":"image.jpg"}
{"filelink":"image.jpg","thumb":"image.jpg","image":"image.jpg"}
{"filelink":"image.jpg","thumb":"image.jpg","image":"image.jpg"}希望有人能帮我解决这个问题,因为我搞不清楚。
提前感谢:D
发布于 2013-06-20 18:39:15
我找到了另一个解决方案:只需更改php文件data.php中的data.json,该文件读取您想要列出的目录,然后转换为json和echo。
这是我现在使用的(演示版,因为我的paypal还没有运行)(路径应该根据你的设置来设置)
在加载编校程序的页面中:
imageGetJson:‘redactor901try/demo/json/data.php’
$path = 'redactor901trial/demo/json/';
$upload_dir = 'images/';
$handle = opendir($upload_dir);
while ($file = readdir($handle)) {
if(!is_dir($upload_dir.$file) && !is_link($upload_dir.$file)) {
$docs[] = $file;
}
}
sort($docs);
foreach($docs as $key=>$file){
$array[] = array(
'filelink' => $path.$upload_dir.$file,
'thumb' => $path.$upload_dir.$file,
'image' => $path.$upload_dir.$file,
'folder' => 'Folder 5'
);
}
echo stripslashes(json_encode($array));希望这能有所帮助,而且还不算太晚;)
问候
史蒂文
https://stackoverflow.com/questions/13691701
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