为什么mySQL语句在比较时会抛出解析错误，而这种比较适用于打印或回显语句？

Question

我正在尝试根据mySQL表查询结果的比较来设置开关。如果我使用print或echo，则查询可以工作，但在尝试使用完全相同的循环进行比较时会抛出语法错误。下面是抛出错误的比较代码。

//Define query for database entry lookup
$sql = "SELECT * FROM email_auth WHERE useremail='$user_email_address'";

//Define result for database entry lookup
$result = mysql_query($sql) or die(mysql_error());

//Find match for email authentication
$email_count = 0;
while($row = mysql_fetch_assoc($result)){
  if ( $row['authID'] == $user_email_auth ) { $validemailrequest = "true" }  //Line 60
  $email_count++;
}

我得到的错误..。

<b>Parse error</b>:  syntax error, unexpected '}' in
<b>/home/user/public_html/send_email.php</b> on line <b>60</b>

但在使用相同的打印时仍然有效...

//Define query for database entry lookup
$sql = "SELECT * FROM email_auth WHERE useremail='$user_email_address'";

//Define result for database entry lookup
$result = mysql_query($sql) or die(mysql_error());

//Find match for email authentication
$email_count = 0;
while($row = mysql_fetch_assoc($result)){
  print $row['authID'];
  $email_count++;
}

Answer 1

条件代码后面似乎缺少分号。

while($row = mysql_fetch_assoc($result)){
    if ( $row['authID'] == $user_email_auth ) { $validemailrequest = "true"; }  //Line 60
    $email_count++;
}

Answer 2

该行缺少分号;，

$validemailrequest = "true";

Answer 3

$validemailrequest = "true"后缺少分号