我在一个http-get中得到xml,签名和签名算法的分离。那么,我该如何验证签名呢?
目前我的代码是:
public void CheckSignature(string response, string sig, string sigalg, byte[] cert)
{
Log("loading cert");
X509Certificate2 cert2 = new X509Certificate2(cert);
bool result = false;
/* response, sigalg and sig are url-decoded or not, doesn't matter :( */
Log("first variant");
var signedString = string.Format(CultureInfo.InvariantCulture, "SAMLResponse={0}&SigAlg={1}", response, sigalg);
result = DoCheck(signedString, sigalg, sig, cert2);
Log("2nd variant");
signedString = string.Format(CultureInfo.InvariantCulture, "SAMLResponse={0}", response);
result = DoCheck(signedString, sigalg, sig, cert2);
Log("3rd variant");
signedString = string.Format(CultureInfo.InvariantCulture, "{0}", response);
result = DoCheck(signedString, sigalg, sig, cert2);
}
private bool DoCheck(string signedString, string sigalg, string sig, X509Certificate2 cert2)
{
try {
var sigDescription = (SignatureDescription)CryptoConfig.CreateFromName(sigalg);
var hashAlg = sigDescription.CreateDigest();
//why is this needed?
hashAlg.ComputeHash(Encoding.UTF8.GetBytes(signedString));
var signature = Convert.FromBase64String(sig);
Log("trying to verify::" + signedString + Environment.NewLine);
X509AsymmetricSecurityKey key = new X509AsymmetricSecurityKey(cert2);
AsymmetricAlgorithm asym_alg = key.GetAsymmetricAlgorithm(sigalg, false);
AsymmetricSignatureDeformatter def = sigDescription.CreateDeformatter(asym_alg);
bool result = false;
result = def.VerifySignature(hashAlg, signature);
//sadly always false.
Log("woop woop:" + result);
return result;
}
catch (Exception ex) {
Log(ex.Message);
Log(ex.StackTrace);
}
return false;
}但是现在,无论我做什么,结果总是错误的。基于https://github.com/KentorIT/authservices/blob/master/Kentor.AuthServices/WebSSO/Saml2RedirectBinding.cs
发布于 2016-06-27 20:44:12
如果您获得形式为SAMLResponse=....SigAlg=...Signature=... (第一个参数也可以是SAMLRequest)的查询字符串,那么您将获得一条使用SAML2 HTTP Redirect绑定的消息。有关其工作原理的说明,请参阅SAML2 Specification。具体地说,您应该阅读绑定规范。
或者,如果您想节省大量的工作,可以找到一个现有的SAML2实现来替代。有几种C#的开源实现可用。
发布于 2016-06-28 20:33:48
井,
我自己发现的。这实际上是rawrequest参数的问题。(我的代码已经对其进行了解析,但无论如何都会失败)
// Can't use the query string params as found in HttpReqeustData
// because they are already unescaped and we need the exact format
// of the original data.
var rawQueryStringParams = request.Url.Query.TrimStart('?')
.Split('&')
.Select(qp => qp.Split('='))
.ToDictionary(kv => kv[0], kv => kv[1]);https://stackoverflow.com/questions/38054044
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