如何合并两个查询？

Question

这是第一个查询：

SELECT 
    SUM(otkupbody_mobile.bruto) AS bruto,
    SUM(otkupbody_mobile.neto) AS neto,
    SUM(otkupbody_mobile.muvla) AS muvla,
    COUNT(*) AS broj_bali
FROM otkupbody_mobile,
     otkupheader_mobile 
WHERE
(
    (otkupheader_mobile.unique_id=otkupbody_mobile.unique_id) 
)

这是第二个：

SELECT
    SUM(otkupbody.bruto) AS bruto,
    SUM(otkupbody.neto) AS neto,
    SUM(otkupbody.muvla) AS muvla,
    COUNT(*) AS broj_bali
FROM otkupbody,
     otkupheader
WHERE
(
    (otkupheader.unique_id=otkupbody.unique_id) 
)

如何进行一次查询才能同时获得两个查询的结果？

Answer 1

如果您想要将列合并在一起，您可以简单地使用它。输出将是包含所有提及列的one行：

Select  A.*
,   B.*
    From    (
    SELECT  SUM(otkupbody_mobile.bruto) AS bruto,
        SUM(otkupbody_mobile.neto) AS neto,
        SUM(otkupbody_mobile.muvla) AS muvla,
        COUNT(*) AS broj_bali
        FROM otkupbody_mobile,
        otkupheader_mobile 
        WHERE   otkupheader_mobile.unique_id=otkupbody_mobile.unique_id
    )   As  A
    ,   (
    SELECT  SUM(otkupbody.bruto) AS bruto,
        SUM(otkupbody.neto) AS neto,
        SUM(otkupbody.muvla) AS muvla,
        COUNT(*) AS broj_bali
        FROM otkupbody,
        otkupheader
        WHERE
        (
        (otkupheader.unique_id=otkupbody.unique_id) 
        )
    )   As  B

或者，如果希望合并行，可以在查询之间使用UNION子句。对于使用union，您应该注意这两个结果必须具有相同的列。输出将是两个行，其中包含first查询的列。如下所示：

    SELECT  SUM(otkupbody_mobile.bruto) AS bruto,
        SUM(otkupbody_mobile.neto) AS neto,
        SUM(otkupbody_mobile.muvla) AS muvla,
        COUNT(*) AS broj_bali
        FROM otkupbody_mobile,
        otkupheader_mobile 
        WHERE   otkupheader_mobile.unique_id=otkupbody_mobile.unique_id
UNION
    SELECT  SUM(otkupbody.bruto) AS bruto,
        SUM(otkupbody.neto) AS neto,
        SUM(otkupbody.muvla) AS muvla,
        COUNT(*) AS broj_bali
        FROM otkupbody,
        otkupheader
        WHERE
        (
        (otkupheader.unique_id=otkupbody.unique_id) 
        )

Answer 2

尝试：

SELECT 
SUM(otkupbody_mobile.bruto) AS bruto,
SUM(otkupbody_mobile.neto) AS neto,
SUM(otkupbody_mobile.muvla) AS muvla,
COUNT(*) AS broj_bali
FROM otkupbody_mobile,
otkupheader_mobile 
WHERE
(
(otkupheader_mobile.unique_id=otkupbody_mobile.unique_id) 
)
UNION ALL
SELECT 
SUM(otkupbody.bruto) AS bruto,
SUM(otkupbody.neto) AS neto,
SUM(otkupbody.muvla) AS muvla,
COUNT(*) AS broj_bali
FROM otkupbody,
otkupheader
WHERE
(
(otkupheader.unique_id=otkupbody.unique_id) 
)

如果您不需要副本，请使用普通UNION而不是UNION ALL

Answer 3

使用全部联合。要进行总结，请对结果使用SUM。如下所示：

select sum(bruto), sum(neto), sum(muvla), sum(broj_bali) from (
  SELECT 
  SUM(otkupbody_mobile.bruto) AS bruto,
  SUM(otkupbody_mobile.neto) AS neto,
  SUM(otkupbody_mobile.muvla) AS muvla,
  COUNT(*) AS broj_bali
  FROM otkupbody_mobile,
  otkupheader_mobile 
  WHERE
  (
  (otkupheader_mobile.unique_id=otkupbody_mobile.unique_id) 
  )
    UNION ALL
  SELECT 
  SUM(otkupbody.bruto) AS bruto,
  SUM(otkupbody.neto) AS neto,
  SUM(otkupbody.muvla) AS muvla,
  COUNT(*) AS broj_bali
  FROM otkupbody,
  otkupheader
  WHERE
  (
  (otkupheader.unique_id=otkupbody.unique_id) 
  )

SQL Fiddle example