我正在尝试从iTunes的.ITC2文件中转储专辑插图。我能施展魔法。但在我尝试转储图像之前,我需要注意它对应的是哪个专辑/曲目/艺术家(三者中的任何一个)。有没有人发现他们是否改变了缓存文件的命名方式?因为,文件名为"2100F8A77FA24601-F2E26C349A9AB861.itc2“的"2100F8A77FA24601”实际上是我的库ID,但是在我的库的XML文件中找不到"F2E26C349A9AB861“。谁能给我解释一下如何将itc2文件与位于XML文件中的曲目关联起来。
reference
我确实从上面的链接获得了一些关于如何设置iTunes的信息。但是这篇文章已经过时了,对于今天的iTunes (v11)版本来说也不是100%正确。
谢谢,索罗德尼
发布于 2013-03-15 01:28:19
实际上,.itc2文件名的第二部分应该是iTunes Library.xml文件中的跟踪持久id。也许你有一个已删除的曲目的艺术作品缓存?
可以通过从XML库中检索到的信息来计算图稿的路径,方法如下:
[itunes library folder]/Album Artwork/Cache/[Library Persistent ID]/XX/YY/ZZ/[Library Persistent ID - Track Persistent ID].itc2其中:
XX: First hex digit from the end in the track persistent id in decimal form
YY: Second hex digit from the end in the track persistent id in decimal form
ZZ: Third hex digit from the end in the track persistent id in decimal form因此,如果:
Library Persistent ID = BEAE1DB35624CB18
Track Persistent ID = 2488665ADBC5420F则该文件夹为:
[itunes library folder]/Album Artwork/Cache/BEAE1DB35624CB18/15/00/02/BEAE1DB35624CB18-2488665ADBC5420F.itc2XML库使用plist xml format,它是iTunes done wrong。尽管如此,您仍然可以通过一些XSLT魔术找到自己的方法。
检查下面的java代码,它将转换iTunes Library.xml,并将计算出的艺术作品路径与艺术家和曲目名称一起放入output.xml
Test.java:
import java.io.File;
import javax.xml.transform.Source;
import javax.xml.transform.Transformer;
import javax.xml.transform.TransformerFactory;
import javax.xml.transform.stream.StreamResult;
import javax.xml.transform.stream.StreamSource;
public class Test {
public static void main(String[] args) throws Exception {
String libraryFolder = "/Path/To/iTunes/";
TransformerFactory factory = TransformerFactory.newInstance();
Source xslt = new StreamSource(new File("convert.xsl"));
Transformer transformer = factory.newTransformer(xslt);
transformer.setParameter("library_folder", libraryFolder);
Source text = new StreamSource(new File(libraryFolder + "iTunes Library.xml"));
transformer.transform(text, new StreamResult(new File(libraryFolder + "output.xml")));
}
}和convert.xsl:
<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output indent="yes"/>
<xsl:param name="library_folder"/>
<xsl:template match="plist">
<xsl:variable name="libid">
<xsl:value-of select="dict/key[. = 'Library Persistent ID']/following-sibling::string[1]"/>
</xsl:variable>
<tracks>
<xsl:apply-templates select="dict/key[. = 'Tracks']/following-sibling::dict[1]/dict" mode="track">
<xsl:with-param name="libid"><xsl:value-of select="$libid"/></xsl:with-param>
</xsl:apply-templates>
</tracks>
</xsl:template>
<xsl:template match="dict" mode="track">
<xsl:param name="libid" />
<entry>
<xsl:variable name="trackid">
<xsl:value-of select="key[. = 'Persistent ID']/following-sibling::string[1]"/>
</xsl:variable>
<xsl:variable name="dig1">
<xsl:call-template name="HexToDecimal">
<xsl:with-param name="hexNumber" select="substring($trackid, string-length($trackid))"/>
</xsl:call-template>
</xsl:variable>
<xsl:variable name="dig2">
<xsl:call-template name="HexToDecimal">
<xsl:with-param name="hexNumber" select="substring($trackid, string-length($trackid) - 1, 1)"/>
</xsl:call-template>
</xsl:variable>
<xsl:variable name="dig3">
<xsl:call-template name="HexToDecimal">
<xsl:with-param name="hexNumber" select="substring($trackid, string-length($trackid) - 2, 1)"/>
</xsl:call-template>
</xsl:variable>
<artist><xsl:value-of select="key[. = 'Artist']/following-sibling::string[1]"/></artist>
<name><xsl:value-of select="key[. = 'Name']/following-sibling::string[1]"/></name>
<track_id><xsl:value-of select="$trackid"/></track_id>
<artwork><xsl:value-of select="concat($library_folder, 'Album Artwork/Cache/',$libid,'/',$dig1,'/',$dig2,'/',$dig3,'/',$libid,'-',$trackid,'.itc2')"/></artwork>
</entry>
</xsl:template>
<!-- Very simple hex to decimal, only one digit -->
<xsl:template name="HexToDecimal">
<xsl:param name="hexNumber" />
<xsl:value-of select="format-number(number(substring-before(substring-after('00/11/22/33/44/55/66/77/88/99/A10/B11/C12/D13/E14/F15/a10/b11/c12/d13/e14/f15/', $hexNumber), '/')),'00')" />
</xsl:template>
</xsl:stylesheet>https://stackoverflow.com/questions/13795842
复制相似问题