我正在尝试做如下所示的xml:
<xml....
<key1>aaa </key1>
<key1>bbb</key1>
<key1>ccc</key1>
</xml>使用python dicttoxml lib
已尝试:
quest_dict = [{'key1': 'aaa'}, {'key1': 'bbb'}, {'key1': 'ccc'}]
request_xml = dicttoxml.dicttoxml(request_dict, attr_type=False, root=False)但是得到的xml并不是很好。感谢您的帮助!
发布于 2018-05-29 20:14:00
您可以创建一个带有重复键的字典,方法是用一个虚拟类包装这些键,然后在该字典上使用dicttoxml。如果顺序很重要,请使用collections.OrderedDict:
from dicttoxml import dicttoxml
from collections import OrderedDict
class Node(object):
def __init__(self, name):
self._name = name
def __str__(self):
return self._name
quest_dict = OrderedDict([(Node('key1'), 'aaa'), (Node('key1'), 'bbb'), (Node('key1'), 'ccc')])
request_xml = dicttoxml(quest_dict, attr_type=False, root=False)
print(request_xml)这将为您提供所需的输出:
b'<key1>aaa</key1><key1>bbb</key1><key1>ccc</key1>'发布于 2020-01-08 07:50:19
您可以使用dicttoxml方法的custom_root和item_func参数获得所需的xml:
import dicttoxml
request_dict = ['aaa', 'bbb', 'ccc']
item_name = lambda x: 'key1'
request_xml = dicttoxml.dicttoxml(request_dict, attr_type=False, custom_root='xml', item_func=item_name)
print(request_xml.decode('utf-8'))输出:
<xml><key1>aaa</key1><key1>bbb</key1><key1>ccc</key1></xml>这个示例的一个扩展是解决在单个xml中有多个重复键的情况,就像<xsd:element minOccurs="0" maxOccurs="unbounded">定义的那样,这是我使用Dave的答案中的OrderedDict无法实现的。最接近的结果是使用item_funcλ来命名父级名称中的项:
import dicttoxml
xml_dict = {}
xml_dict['key1'] = ['aaa', 'bbb', 'ccc']
xml_dict['another-key'] = ['a','b','c']
item_name = lambda x: x
request_xml = dicttoxml.dicttoxml(xml_dict, attr_type=False, custom_root='xml', item_func=item_name)
print(request_xml.decode('utf-8'))但是我们你必须从结果中删除父母:
<xml>
<key1>
<key1>aaa</key1>
...可以应用Clean (显式):
xml_str = request_xml.decode("utf-8", "strict")
xml_str = xml_str.replace('<key1><key1>', '<key1>').replace('</key1></key1>', '</key1>')
xml_str = xml_str.replace('<another-key><another-key>', '<another-key>').replace('</another-key></another-key>', '</another-key>')
print(xml_str)结果:
<xml>
<key1>aaa</key1>
...
<another-key>a</another-key>
...
</xml>https://stackoverflow.com/questions/37932344
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