比较并查找两个字符串(时间)之间的值

Question

我有一个字符串数组，存储每天的公交车间隔，如下所示

eg. ["6:30", "6:45", "7:00", "7:15", "7:30", "7.45"..................]

我想让程序从数组中找到最接近当天的时间和系统上的时间。

例如：在上面的字符串数组中，假设我的系统时间是7:35，那么它应该显示7:30和7:45作为最近的时间

Answer 1

我希望这能帮到你。

public class TestClass {

    public static void main(String[] args){

        String arr[]={"06:30","07:00","07:30","14:20","14:50","18:20"};
         Calendar cal = Calendar.getInstance();
            SimpleDateFormat sdf = new SimpleDateFormat("HH:mm");
            System.out.println("Your system time is :"+ sdf.format(cal.getTime()) );
            System.out.println("So nearest timings are...");
            String sys[]=sdf.format(cal.getTime()).toString().split(":");
           // System.out.println(sys[0]);
        for(String st:arr){
            if(st.startsWith(sys[0]))
                System.out.println(st);
            }
        }   
}

。

output would be : 
Your system time is :14:47 
So nearest timings are... 
14:20 14:50

Answer 2

尝尝这个

    String[] arr =new String[]{"6:30", "6:45", "7:00", "7:15", "7:30", "7:45"};
        Calendar cal = Calendar.getInstance();
        SimpleDateFormat sdf = new SimpleDateFormat("HHmm");
        String currentTime=sdf.format(cal.getTime());
        //nus interval 
        Integer interval=15;

        for (String string : arr) {
            if(Math.abs(Integer.valueOf(string.replaceFirst(":", ""))-Integer.valueOf(currentTime))<interval){
                System.out.println(string);
            } 
        }