我尝试发送reqeuest到server...and,直到请求没有响应。我想执行一个循环,打印integers..problem。如果我的循环一直在继续,如果我一直执行到100,它会打印100个值,如果到1000,它会打印1000个值。我想要的是循环应该依赖于响应。一旦响应发生,循环线程就应该停止...
public class ServiceInteraction {
FutureTask<JSONArray> task;
public JSONArray addUser(List<BasicNameValuePair> postPairs_interaction){
JSONArray jArray;
task = new FutureTask<JSONArray>(new Service_C(postPairs_interaction));
ExecutorService pool = Executors.newFixedThreadPool(2);
pool.submit(task);
for(int i = 0 ; i < 1000; i++){
System.out.println("value is "+i);
}//End of for loop
try{
return (jArray = task.get());
}catch(InterruptedException e){
return null;
}catch(ExecutionException e){
return null;
}
}//End Of addUser这是我的service_c类代码..。
public Service_C(List<BasicNameValuePair> postPairs) {
this.postPairs = postPairs;
}
@Override
public JSONArray call() throws Exception {
HttpClient httpclient = new DefaultHttpClient();
HttpPost post = new HttpPost("http://10.0.0.62:8080/IDocWS/"+postPairs.get(0).getValue());
post.setEntity(new UrlEncodedFormEntity(postPairs));
ResponseHandler respHandler = new BasicResponseHandler();
String responseData = (String) httpclient.execute(post,respHandler);
try {
JSONArray jArray;
jArray = new JSONArray(responseData);
return jArray;
} catch (JSONException ex) {
Logger.getLogger(Service.class.getName()).log(Level.SEVERE, null, ex);
System.out.println("Error in getting response from the user");
return null;
}
}//End of call method发布于 2012-11-20 15:08:25
您可以尝试这样做:
for (int i = 0;;i++){
if (task.isDone()) {
break;
}
System.out.println("value is "+i);
}https://stackoverflow.com/questions/13467983
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