如何使用java在xml文件中包含xsl样式表

Question

作为selenium的一部分，我们将生成xml形式的结果文件。现在我们正在生成类似"ReportManager.xml“的文件，我们想在第二行添加一个xsl样式表链接，

以下是:Report Magaer.xml的代码

<?xml version="1.0" encoding="UTF-8"?>
<ReportManager><SmokeTest><Version DisplayName="ERP Build: ERP 9">
<Family DisplayName="Module">
<Product DisplayName="Branch Setup"/>
<Product DisplayName="Academics Module"/>
<Product DisplayName="Admission Process"/>
<Product DisplayName="Examination Settings"/>
<Product DisplayName="Examination Production"/>
<Product DisplayName="Delete Master Activity Remarks">
<Report ActualResult="Activity Deleted :etetettre is shown" Executed="Wed Jan 20 12:08:02 IST 2016" ExpectedResult="Activity Deleted :etetettre should be shown" Status="Pass" StepNumber="1"/>
<Report ActualResult="Activity Deleted :wfdreqfreqwreeeeeee is shown" Executed="Wed Jan 20 12:08:21 IST 2016" ExpectedResult="Activity Deleted :wfdreqfreqwreeeeeee should be shown" Status="Pass" StepNumber="1"/>
</Product>
</Family>
</Version>
</SmokeTest>
</ReportManager>

现在我想包括下面这行

<?xml-stylesheet type='text/xsl' href='ReportManager.xsl'?>

在动态的第二行，请让我知道我们如何用java编写这个脚本。

Answer 1

我不知道这实际上是什么意思，但是如果您已经有了xsl和输入xml，那么可以使用下面的java代码对它们进行转换，希望它能有所帮助。

import java.io.File;
import java.io.IOException;
import java.net.URISyntaxException;

import javax.xml.transform.Source;
import javax.xml.transform.Transformer;
import javax.xml.transform.TransformerException;
import javax.xml.transform.TransformerFactory;
import javax.xml.transform.stream.StreamResult;
import javax.xml.transform.stream.StreamSource;

public class XMLTransformationEndingTag {

    public static void main(String[] args) throws IOException, URISyntaxException, TransformerException {

        String XMLFile="<path for your xml file>";
        String XSLFile="<path for your xsl file>";

        TransformerFactory fac = TransformerFactory.newInstance();
        Source xslt= new StreamSource(new File(XSLFile));
        Transformer trans = fac.newTransformer(xslt);

        Source text=new StreamSource(new File(XMLFile));
        trans.transform(text, new StreamResult(new File("file.xml")));

    }

}