当我的分数增加时调用一个随机的SKAction？

Question

我有三个SKAction变量，它们都会改变屏幕上球的颜色。我想让它在我的分数增加时，从三个动作中随机选择一个动作。这个是可能的吗？如果你能帮我的话那就太好了。谢谢。

到目前为止，我的代码如下：

let colorize1 = SKAction.colorizeWithColor(.redColor(), colorBlendFactor: 1.0, duration: 0.001)

let colorize2 = SKAction.colorizeWithColor(.greenColor(), colorBlendFactor: 1.0, duration: 0.001)

let colorize3 = SKAction.colorizeWithColor(.blueColor(), colorBlendFactor: 1.0, duration: 0.001)

if score == 0 {
        Ball.runAction(colorize1)

    }

每当“这件事”发生时，我有一个for循环递增我的分数。当我的分数递增1时，我想让球做colorize1，colorize2或colorize3。

提前感谢您的帮助。

Answer 1

let colorize1 = SKAction.colorizeWithColor(.redColor(), colorBlendFactor: 1.0, duration: 0.001)

let colorize2 = SKAction.colorizeWithColor(.greenColor(), colorBlendFactor: 1.0, duration: 0.001)

let colorize3 = SKAction.colorizeWithColor(.blueColor(), colorBlendFactor: 1.0, duration: 0.001)

let actions = [colorize1, colorize2, colorize3]

let randomIndex = Int(arc4random_uniform(3))

let action = actions[randomIndex]

let b = Ball()
b.runAction(action)