与conduit sinkParser相结合的伊森deriveJSON

Question

继续我对conduit和aeson的探索，在这个来自Yesod book的(稍微修改过的)代码片段中，我将如何使用我自己的数据类型而不是Value。

{-# LANGUAGE OverloadedStrings, TemplateHaskell #-}
import Network.Wai (Response, responseLBS, Application, requestBody)
import Network.HTTP.Types (status200, status400)
import Network.Wai.Handler.Warp (run)
import Data.Aeson.Parser (json)
import Data.Conduit.Attoparsec (sinkParser)
import Control.Monad.IO.Class (liftIO)
import Data.Aeson (Value(..), encode, object, (.=))
import Control.Exception (SomeException)
import Data.ByteString (ByteString)
import Data.Conduit (ResourceT, ($$))
import Control.Exception.Lifted (handle)

import qualified Data.HashMap.Strict as M
import Data.Aeson.TH (deriveJSON)

-- I ADDED THIS

data JSONRequest = JSONRequest {
    command :: ByteString,
    params :: M.HashMap ByteString ByteString
}

deriveJSON id ''JSONRequest

-- END OF WHAT I ADDED

main :: IO ()
main = run 3000 app

app :: Application
app req = handle invalidJson $ do
    value <- requestBody req $$ sinkParser json
    newValue <- liftIO $ dispatch value
    return $ responseLBS
        status200
        [("Content-Type", "application/json")]
        $ encode newValue

invalidJson :: SomeException -> ResourceT IO Response
invalidJson ex = return $ responseLBS
    status400
    [("Content-Type", "application/json")]
    $ encode $ object
        [ ("message" .= show ex)
        ]

-- Application-specific logic would go here.
dispatch :: Value -> IO Value
dispatch = return

基本上，我希望将dispatch的类型更改为JSONRequest -> IO JSONRequest。如何告诉解析器使用我自己的fromJSON派生实例？

我试着添加一个类型声明，祈祷json上的多态返回类型，但我意识到它是严格对值的。

Answer 1

看看类型，难道你不需要在来自json的结果上fmap你的fromJSON吗？有了适用于dispatch的签名，我们只需要：

-- import Data.Aeson
app :: Application
app req = handle invalidJson $ do
      result <- requestBody req $$ sinkParser (fmap fromJSON json)
      next_result <- liftIO $ dispatch result
      return $ responseLBS status200 [("Content-Type", "application/json")] 
             $ encode next_result   

dispatch :: Result JSONRequest -> IO JSONRequest
dispatch (Error str) = undefined
dispatch (Success jsonreq) = return jsonreq

但可能会写得更清楚一些：

-- import Data.Aeson
-- import qualified Data.Attoparsec as Atto
toRequest ::    Value -> Result JSONRequest
toRequest = fromJSON   -- specialized now to your fromJSON

jsonRequestParser :: Atto.Parser (Result JSONRequest)
jsonRequestParser = fmap toRequest json 

app :: Application
app req = handle invalidJson $ do
      result <- requestBody req $$ sinkParser jsonRequestParser
      next_result <- liftIO $ dispatch result
      return $ responseLBS status200 [("Content-Type", "application/json")]
             $ encode next_result   

dispatch :: Result JSONRequest -> IO JSONRequest
dispatch (Error str) = undefined
dispatch (Success jsonreq) = return jsonreq

我让解析器返回一个Result JSONRequest，所以dispatch也在处理错误情况，这可能意味着你需要以某种方式处理异常？