如何检查FtpWebRequest超时
Try
Dim request As FtpWebRequest = CType(WebRequest.Create("ftp://"), FtpWebRequest)
request.Method = WebRequestMethods.Ftp.ListDirectoryDetails
request.Timeout = 4000
' If 'TimeOut' = False Then
request.Credentials = New NetworkCredential("u", "p")
Using response As FtpWebResponse = CType(request.GetResponse(), FtpWebResponse)
Using responseStream As Stream = response.GetResponseStream()
Using reader As New StreamReader(responseStream)
'do this
End Using
End Using
End Using
'End If
Catch ex As Exception
End Try发布于 2012-11-04 01:45:42
您通常可以设置超时值,如果在上述时间内没有响应,则会抛出带有status属性的WebException,因为Timeout.You可以捕获并适当地处理它。
Try
//your code for request/response
Catch ex As WebException
MsgBox("Exception reason "&ex.State)
End Tryhttps://stackoverflow.com/questions/13211703
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