我使用以下代码从我的表中获取内容。但我需要稍微更改一下JSON的输出。
$rows = array();
if(isset($_GET['fruitName'])) {
$stmt = $pdo->prepare("SELECT variety FROM fruit WHERE name = ? ORDER BY variety");
$stmt->execute(array($_GET['fruitName']));
$rows = $stmt->fetchAll(PDO::FETCH_ASSOC);
}
echo json_encode($rows);使用上面的代码,它如下所示:
[{"variety":"Apple"},{"variety":"Banana"},{"variety":"Orange"},{"variety":"Pear"}]但我希望它是这样的:
[{"optionValue": "Apple", "optionDisplay": "Apple"}, {"optionValue": "Banana", "optionDisplay": "Banana"}, {"optionValue": "Orange", "optionDisplay": "Orange"}, {"optionValue": "Pear", "optionDisplay": "Pear"}]发布于 2012-10-19 22:18:39
一种解决方案是调整SQL查询,如下所示:
SELECT variety AS optionValue, variety AS optionDisplay FROM fruit WHERE name = ? ORDER BY variety另一种方法是分别解析每一行,然后手动构建数组。因此,不是
$rows = $stmt->fetchAll(PDO::FETCH_ASSOC);你可以使用
$rows = array();
while( $row = $stmt->fetch(PDO::FETCH_ASSOC) ) {
$rows[] = array( 'optionValue' => $row['variety'], 'optionDisplay' => $row['variety'] );
}发布于 2012-10-19 22:16:09
将select语句更改为
"SELECT variety as `optionValue`,variety as `optionDisplay` FROM fruit WHERE name = ? ORDER BY variety"发布于 2012-10-19 22:16:24
$data = '[{"variety":"Apple"},{"variety":"Banana"},{"variety":"Orange"},{"variety":"Pear"}]';
$arr = new array();
// loop through the data
foreach($data as $k => $v){
// build an array of values formatted as you want
$arr[] = '{"optionValue": "'.$v.'", "optionDisplay": "'.$v.'"}}';
}
// join all the values togetger, and pass through json parser
$obj = json_decode(',', "[" . implode($arr) . "]");
// should return in your desired format...https://stackoverflow.com/questions/12976030
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