我想从表a、b、c中提取数据,但要按表响应的最新数据排序
工作台的结构是这样的(简化):
casework_id | problem | user_id
------------+-----------+-------
1 | Problem1 | 1
2 | Problem2 | 2
3 | Problem3 | 1
4 | Problem4 | 3表user具有以下结构(简化):
user_id | name
--------+-----------------
1 | peter
2 | Sam
3 | Tom
4 | Steve表响应结构如下(简化):
response_id | response | casework_id | created
------------+-----------+--------------+-------
1 | responce1 | 1 | 2012-10-14 11:28:31
2 | responce2 | 1 | 2012-9-10 11:28:31
3 | responce3 | 1 | 2012-9-2 11:28:31
4 | responce4 | 3 | 2012-8-3 11:28:31
4 | responce5 | 3 | 2012-8-2 11:28:31我正在寻找按最新响应和按casework_id分组来获取数据的查询
I. e. required out put is
casework_id | problem | name | responce | created
------------+-----------+-------+-----------+---------
1 | Problem1 | peter | responce1 | 2012-10-14 11:28:31
2 | Problem2 | Sam | Null | Null
3 | Problem3 | peter | responce4 | 2012-8-3 11:28:31
4 | Problem4 | Tom | Null | Null如果你们这些好心人中有人能给我指个方向,我将不胜感激。
发布于 2012-10-16 18:19:50
您可以使用以下内容:
select c.casework_id,
c.problem,
u.name,
r2.response,
r1.created
from casework c
left join user u
on c.user_id = u.user_id
left join
(
select max(created) created, casework_id
from response r
group by casework_id
) r1
on c.casework_id = r1.casework_id
left join response r2
on r1.created = r2.created
and r1.casework_id = r2.casework_id请参阅SQL Fiddle with Demo
如果您希望既包括创建案例工作的用户,又包括做出响应的用户,则需要在user表上联接两次:
select c.casework_id,
c.problem,
u1.name CreatedByName,
r2.response,
r1.created,
u2.name ReponseName
from casework c
left join user u1
on c.user_id = u1.user_id
left join
(
select max(created) created, casework_id
from response r
group by casework_id
) r1
on c.casework_id = r1.casework_id
left join response r2
on r1.created = r2.created
and r1.casework_id = r2.casework_id
left join user u2
on r2.user_id = u2.user_id请参阅SQL Fiddle with demo
发布于 2012-10-16 18:18:21
我还没有测试过,但它可能会给你一个概念
select c.casework_id, c.problem,
(select name from user u where u.user_id = c.user_id ),
(select r.reponse from response r where r.casework_id = c.casework_id ORDER BY r.created DESC LIMIT 1),
(select r.created from response r where r.casework_id = c.casework_id ORDER BY r.created DESC LIMIT 1),
from casework c发布于 2012-10-16 18:19:02
SELECT responce.casework_id, problem, name, responce, created
FROM responce
JOIN
(SELECT casework_id, problem, name
FROM casework JOIN user
ON casework.userid=user.userid) AS A
ON responce.casework_id=A.casework_id
ORDER BY responce, responce.casework_idhttps://stackoverflow.com/questions/12912259
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