从物理文件实例化IFormFile

Question

我有一个物理文件，我想将它传递给需要IFormFile类型(用于单元测试)的控制器方法。

我找不到任何实例化IFormFile接口的类，这意味着我无法创建一个。

如何将我的物理文件转换为IFormFile

Answer 1

让我们假设您有一个接受IFormInfo的控制器方法

[HttpPost]
public Task<IActionResult> Upload(IFormFile file) {

    FileDetails fileDetails = null;
    using (var reader = new StreamReader(file.OpenReadStream())) {
        var fileContent = reader.ReadToEnd();
        ContentDispositionHeaderValue parsedContentDisposition = null;
        if (ContentDispositionHeaderValue.TryParse(file.ContentDisposition, out parsedContentDisposition)) {
            fileDetails = new FileDetails {
                Filename = parsedContentDisposition.FileName,
                Content = fileContent
            };
        }
    }

    return Task.FromResult((IActionResult)fileDetails);

}

使用Moq这样的模拟框架。您可以使用物理文件模拟IFormFile

[TestMethod]
public async Task Controller_Should_Upload_FormFile() {
    // Arrange.
    var fileMock = new Mock<IFormFile>();
    var physicalFile = new FileInfo("filePath");
    var ms = new MemoryStream();
    var writer = new StreamWriter(ms);
    writer.Write(physicalFile.OpenRead());
    writer.Flush();
    ms.Position = 0;
    var fileName = physicalFile.Name;
    //Setup mock file using info from physical file
    fileMock.Setup(_ => _.FileName).Returns(fileName);
    fileMock.Setup(_ => _.Length).Returns(ms.Length);
    fileMock.Setup(_ => _.OpenReadStream()).Returns(ms);
    fileMock.Setup(_ => _.ContentDisposition).Returns(string.Format("inline; filename={0}", fileName));
    //...setup other members as needed.

    var sut = new MyController();
    var file = fileMock.Object;

    // Act.
    var result = await sut.Upload(file);

    //Assert.
    Assert.IsInstanceOfType(result, typeof(IActionResult));
}

mock的排列甚至可以提取到一个扩展方法中以供重用。

public static IFormFile AsMockIFormFile(this FileInfo physicalFile) {
    var fileMock = new Mock<IFormFile>();
    var ms = new MemoryStream();
    var writer = new StreamWriter(ms);
    writer.Write(physicalFile.OpenRead());
    writer.Flush();
    ms.Position = 0;
    var fileName = physicalFile.Name;
    //Setup mock file using info from physical file
    fileMock.Setup(_ => _.FileName).Returns(fileName);
    fileMock.Setup(_ => _.Length).Returns(ms.Length);
    fileMock.Setup(m => m.OpenReadStream()).Returns(ms);
    fileMock.Setup(m => m.ContentDisposition).Returns(string.Format("inline; filename={0}", fileName));
    //...setup other members (code removed for brevity)


    return fileMock.Object;
}

并像这样使用

var physicalFile = new FileInfo("filePath");
IFormFile formFile = physicalFile.AsMockIFormFile();

Answer 2

您可以实例化FormFile。它实现了IFormFile。

.Net核心3.1中的示例(假设'file‘是物理路径和文件)：

using var stream = new MemoryStream(File.ReadAllBytes(file).ToArray());
var formFile = new FormFile(stream, 0, stream.Length, "streamFile", file.Split(@"\").Last());

Answer 3

我尝试了Nkosi的答案(使用.NET Core3.1)，但它只返回"System.IO.FileStream“作为文件内容！可能是因为它将FileStream对象从physicalFile.OpenRead()写入输出流，而不是流的实际内容。这个修改后的版本适用于我：

    public static IFormFile AsMockIFormFile(this FileInfo physicalFile)
    {
        var fileMock = new Mock<IFormFile>();
        var ms = new MemoryStream();
        var writer = new StreamWriter(ms);
        using (FileStream fs = physicalFile.OpenRead())
        {
            byte[] b = new byte[1024];
            UTF8Encoding temp = new UTF8Encoding(true);

            while (fs.Read(b, 0, b.Length) > 0)
            {
                writer.WriteLine(temp.GetString(b));
            }
        }
        writer.Flush();
        ms.Position = 0;
        var fileName = physicalFile.Name;
        //Setup mock file using info from physical file
        fileMock.Setup(_ => _.FileName).Returns(fileName);
        fileMock.Setup(_ => _.Length).Returns(ms.Length);
        fileMock.Setup(m => m.OpenReadStream()).Returns(ms);
        fileMock.Setup(m => m.ContentDisposition).Returns(string.Format("inline; filename={0}", fileName));
        //...setup other members as needed

        return fileMock.Object;
    }