blocks|key|3557641|text|它似乎在抱怨\x08，你需要避开它。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3557642|编辑：|BOLD|3557643|或者，您可以使用recover让解析器忽略错误|3557644|from+lxml+import+etree
parser+=+etree.XMLParser(recover=True)
etree.fromstring(xmlstring,+parser=parser)|code-block|syntax|javascript|3557645|entityMap^0|6|4|0|0|3|0|8|7|0|0^^$0|@$1|2|3|4|5|6|7|R|8|@$9|S|A|T|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|U|8|@$9|V|A|W|B|H]]|D|@]|E|$]]|$1|I|3|J|5|6|7|X|8|@$9|Y|A|Z|B|C]]|D|@]|E|$]]|$1|K|3|L|5|M|7|10|8|@]|D|@]|E|$N|O]]|$1|P|3|-4|5|6|7|11|8|@]|D|@]|E|$]]]|Q|$]]

It seems to complain about <code>\x08</code> you will need to escape that.

Edit: 

Or you can have the parser ignore the errors using <code>recover</code>

<pre><code>from lxml import etree
parser = etree.XMLParser(recover=True)
etree.fromstring(xmlstring, parser=parser)
</code></pre>

blocks|key|5196468|text|我也遇到了同样的错误(对于ElementTree)。在我的例子中，这是因为编码，我能够在不使用外部库的情况下解决它。希望这能帮助其他人根据标题找到这个问题。(reference)|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|5196469|import+xml.etree.ElementTree+as+ET
parser+=+ET.XMLParser(encoding="utf-8")
tree+=+ET.fromstring(xmlstring,+parser=parser)|code-block|syntax|javascript|5196470|EDIT：根据评论，这个答案可能已经过时了。但当它被回答时，这确实起到了作用...|style|BOLD|5196471|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/9209547/2697658^0|27|9|0|0|0|0|4|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@$A|V|B|W|1|X]]|C|$]]|$1|D|3|E|5|F|7|Y|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|Z|8|@$A|10|B|11|K|L]]|9|@]|C|$]]|$1|M|3|-4|5|6|7|12|8|@]|9|@]|C|$]]]|N|$O|$5|P|Q|R|C|$S|T]]]]

I was having the same error (with ElementTree). In my case it was because of encodings, and I was able to solve it without having to use an external library. Hope this helps other people finding this question based on the title. (<a href="https://stackoverflow.com/a/9209547/2697658">reference</a>)

<pre><code>import xml.etree.ElementTree as ET
parser = ET.XMLParser(encoding="utf-8")
tree = ET.fromstring(xmlstring, parser=parser)
</code></pre>

EDIT: Based on comments, this answer might be outdated. But this did work back when it was answered...

blocks|key|5196437|text|请参阅另一个问题的this+answer和XML规范的according+part。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|5196438|退格符U%2B0008是XML文档中的无效字符。它必须表示为转义实体&#8;，并且不能简单地出现。|style|CODE|5196439|如果需要处理此XML片段，则必须在将其提供给XML解析器之前替换s中的\x08。|5196440|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/5110103/113195|1|http://www.w3.org/TR/xml/#charsets|2|http://codepoints.net/U%2B0008^0|9|B|0|R|E|1|0|W|4|3|6|2|0|W|1|Z|4|0^^$0|@$1|2|3|4|5|6|7|V|8|@]|9|@$A|W|B|X|1|Y]|$A|Z|B|10|1|11]]|C|$]]|$1|D|3|E|5|6|7|12|8|@$A|13|B|14|F|G]]|9|@$A|15|B|16|1|17]]|C|$]]|$1|H|3|I|5|6|7|18|8|@$A|19|B|1A|F|G]|$A|1B|B|1C|F|G]]|9|@]|C|$]]|$1|J|3|-4|5|6|7|1D|8|@]|9|@]|C|$]]]|K|$L|$5|M|N|O|C|$P|Q]]|R|$5|M|N|O|C|$P|S]]|T|$5|M|N|O|C|$P|U]]]]

See <a href="https://stackoverflow.com/a/5110103/113195">this answer</a> to another question and the <a href="http://www.w3.org/TR/xml/#charsets" rel="nofollow noreferrer">according part</a> of the XML spec.

The backspace <a href="http://codepoints.net/U+0008" rel="nofollow noreferrer">U+0008</a> is an invalid character in XML documents. It must be represented as escaped entity <code>&amp;#8;</code> and cannot occur plainly.

If you need to process this XML snippet, you must replace <code>\x08</code> in <code>s</code> before feeding it into an XML parser.

blocks|key|3074301|text|上面的修复方法对我都不起作用。唯一起作用的是使用BeautifulSoup而不是ElementTree，如下所示：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3074302|from+bs4+import+BeautifulSoup

with+open("data/myfile.xml")+as+fp:
++++soup+=+BeautifulSoup(fp,+'xml')|code-block|syntax|javascript|3074303|然后，您可以搜索树，如下所示：|3074304|soup.find_all('mytag')|3074305|entityMap^0|O|D|14|B|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]|$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|W|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|Y|8|@]|D|@]|E|$]]]|P|$]]

None of the above fixes worked for me. The only thing that worked was to use <code>BeautifulSoup</code> instead of <code>ElementTree</code> as follows:

<pre><code>from bs4 import BeautifulSoup

with open("data/myfile.xml") as fp:
 soup = BeautifulSoup(fp, 'xml')
</code></pre>

Then you can search the tree as:

<pre><code>soup.find_all('mytag')
</code></pre>

blocks|key|3557785|text|这段代码对我来说很有效。我有一个解析批量XML文件的问题。我不得不把它们编码成'iso-8859-5‘|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3557786|import+xml.etree.ElementTree+as+ET

tree+=+ET.parse(filename,+parser+=+ET.XMLParser(encoding+=+'iso-8859-5'))|code-block|syntax|javascript|3557787|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This code snippet worked for me. I have an issue with the parsing batch of XML files. I had to encode them to 'iso-8859-5'

<pre><code>import xml.etree.ElementTree as ET

tree = ET.parse(filename, parser = ET.XMLParser(encoding = 'iso-8859-5'))
</code></pre>

blocks|key|3074289|text|我的gottcha的解决方案，使用Python的ElementTree...这包含无效令牌错误：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3074290|#+-*-+coding:+utf-8+-*-
import+xml.etree.ElementTree+as+ET

xml+=+u"""<?xml+version='1.0'+encoding='utf8'?>
<osm+generator="pycrocosm+server"+version="0.6"><changeset+created_at="2017-09-06T19:26:50.302136%2B00:00"+id="273"+max_lat="0.0"+max_lon="0.0"+min_lat="0.0"+min_lon="0.0"+open="true"+uid="345"+user="john"><tag+k="test"+v="Съешь+же+ещё+этих+мягких+французских+булок+да+выпей+чаю"+/><tag+k="foo"+v="bar"+/><discussion><comment+data="2015-01-01T18:56:48Z"+uid="1841"+user="metaodi"><text>Did+you+verify+those+street+names?</text></comment></discussion></changeset></osm>"""

xmltest+=+ET.fromstring(xml.encode("utf-8"))|code-block|syntax|javascript|3074291|但是，它适用于在编码类型中添加连字符：|3074292|<?xml+version='1.0'+encoding='utf-8'?>|3074293|最奇怪的是。Someone在python+docs中找到了这个脚注|offset|length|3074294|3074295|输出中包含的编码字符串应符合相应的标准。例如，“UTF-8”是有效的，但“UTF8”是无效的。|blockquote|3074296|3074297|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/20526524/4288232|1|http://docs.python.org/2/library/xml.dom.minidom.html#id3^0|0|0|0|0|6|7|0|E|B|1|0|0|0|0^^$0|@$1|2|3|4|5|6|7|13|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|14|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|15|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|16|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|17|8|@]|9|@$M|18|N|19|1|1A]|$M|1B|N|1C|1|1D]]|A|$]]|$1|O|3|-4|5|6|7|1E|8|@]|9|@]|A|$]]|$1|P|3|Q|5|R|7|1F|8|@]|9|@]|A|$]]|$1|S|3|-4|5|6|7|1G|8|@]|9|@]|A|$]]|$1|T|3|-4|5|6|7|1H|8|@]|9|@]|A|$]]]|U|$V|$5|W|X|Y|A|$Z|10]]|11|$5|W|X|Y|A|$Z|12]]]]

A solution for gottcha for me, using Python's ElementTree... this has the invalid token error:

<pre><code># -*- coding: utf-8 -*-
import xml.etree.ElementTree as ET

xml = u"""&lt;?xml version='1.0' encoding='utf8'?&gt;
&lt;osm generator="pycrocosm server" version="0.6"&gt;&lt;changeset created_at="2017-09-06T19:26:50.302136+00:00" id="273" max_lat="0.0" max_lon="0.0" min_lat="0.0" min_lon="0.0" open="true" uid="345" user="john"&gt;&lt;tag k="test" v="Съешь же ещё этих мягких французских булок да выпей чаю" /&gt;&lt;tag k="foo" v="bar" /&gt;&lt;discussion&gt;&lt;comment data="2015-01-01T18:56:48Z" uid="1841" user="metaodi"&gt;&lt;text&gt;Did you verify those street names?&lt;/text&gt;&lt;/comment&gt;&lt;/discussion&gt;&lt;/changeset&gt;&lt;/osm&gt;"""

xmltest = ET.fromstring(xml.encode("utf-8"))
</code></pre>

However, it works with the addition of a hyphen in the encoding type:

<pre><code>&lt;?xml version='1.0' encoding='utf-8'?&gt;
</code></pre>

Most odd. <a href="https://stackoverflow.com/a/20526524/4288232">Someone</a> found this footnote in the <a href="http://docs.python.org/2/library/xml.dom.minidom.html#id3" rel="nofollow noreferrer">python docs</a>:

<blockquote>
 The encoding string included in XML output should conform to the
 appropriate standards. For example, “UTF-8” is valid, but “UTF8” is
 not.
</blockquote>

blocks|key|3557749|text|这很可能是编码错误。例如，我有一个用UTF-8-BOM编码的xml文件(从Notepad%2B%2B编码菜单中选中)，得到了类似的错误消息。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3557750|解决方法(Python+3.6)|3557751|import+io
from+xml.etree+import+ElementTree+as+ET

with+io.open(file,+'r',+encoding='utf-8-sig')+as+f:
++++contents+=+f.read()
++++tree+=+ET.fromstring(contents)|code-block|syntax|javascript|3557752|检查xml文件的编码。如果它使用不同的编码，请相应地更改'utf-8-sig‘。|3557753|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|N|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|O|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

This is most probably an encoding error. For example I had an xml file encoded in UTF-8-BOM (checked from the Notepad++ Encoding menu) and got similar error message. 

The workaround (Python 3.6)

<pre><code>import io
from xml.etree import ElementTree as ET

with io.open(file, 'r', encoding='utf-8-sig') as f:
 contents = f.read()
 tree = ET.fromstring(contents)
</code></pre>

Check the encoding of your xml file. If it is using different encoding, change the 'utf-8-sig' accordingly.

blocks|key|5196537|text|在对整个WWW进行了大量搜索之后，我才发现如果想让XML解析器正常工作，就必须对某些字符进行转义！下面是我是如何做到这一点并为自己工作的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5196538|escape_illegal_xml_characters+=+lambda+x:+re.sub(u'[\x00-\x08\x0b\x0c\x0e-\x1F\uD800-\uDFFF\uFFFE\uFFFF]',+'',+x)|code-block|syntax|javascript|5196539|像往常一样使用它：|5196540|ET.XML(escape_illegal_xml_characters(my_xml_string))+#instead+of+ET.XML(my_xml_string)|5196541|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

After lots of searching through the entire WWW, I only found out that you have to escape certain characters if you want your XML parser to work! Here's how I did it and worked for me:

<pre><code>escape_illegal_xml_characters = lambda x: re.sub(u'[\x00-\x08\x0b\x0c\x0e-\x1F\uD800-\uDFFF\uFFFE\uFFFF]', '', x)
</code></pre>

And use it like you'd normally do:

<pre><code>ET.XML(escape_illegal_xml_characters(my_xml_string)) #instead of ET.XML(my_xml_string)
</code></pre>

blocks|key|3074284|text|我也遇到过类似的问题。在我的特殊情况下，我终于找到了根本原因。如果您从位于同一文件夹中的多个XML文件中读取数据，则还将解析.DS_Store文件。在解析之前添加此条件|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3074285|for+file+in+files:
++++if+file.endswith('.xml'):
+++++++run_your_code...|code-block|syntax|javascript|3074286|这个技巧对我也有帮助。|3074287|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

I have been in stuck with similar problem. Finally figured out the what was the root cause in my particular case. If you read the data from multiple XML files that lie in same folder you will parse also .DS_Store file.
Before parsing add this condition

<pre><code>for file in files:
 if file.endswith('.xml'):
 run_your_code...
</code></pre>

This trick helped me as well

blocks|key|5287152|text|帮助我解决这个错误的是Juan的答案-+https://stackoverflow.com/a/20204635/4433222，但还不够--经过努力，我发现一个XML文件需要用不带BOM编码的UTF-8保存。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|5287153|该解决方案对“普通”UTF-8不起作用。|5287154|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/20204635/4433222^0|K|18|0|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@]|9|@$A|O|B|P|1|Q]]|C|$]]|$1|D|3|E|5|6|7|R|8|@]|9|@]|C|$]]|$1|F|3|-4|5|6|7|S|8|@]|9|@]|C|$]]]|G|$H|$5|I|J|K|C|$L|M]]]]

What helped me with that error was Juan's answer - <a href="https://stackoverflow.com/a/20204635/4433222">https://stackoverflow.com/a/20204635/4433222</a>
But wasn't enough - after struggling I found out that an XML file needs to be saved with UTF-8 without BOM encoding.

The solution wasn't working for "normal" UTF-8.

blocks|key|5196531|text|唯一对我有效的是我必须在打开文件时添加模式和编码，如下所示：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5196532|with+open(filenames[0],+mode='r',encoding='utf-8')+as+f:
+++++readFile()|code-block|syntax|javascript|5196533|否则，如果我简单地这样做，它每次都会失败，并出现无效令牌错误：|5196534|+f+=+open(filenames[0],+'r')
+readFile()|5196535|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

The only thing that worked for me is I had to add mode and encoding while opening the file like below:

<pre><code>with open(filenames[0], mode='r',encoding='utf-8') as f:
 readFile()
</code></pre>

Otherwise it was failing every time with invalid token error if I simply do this:

<pre><code> f = open(filenames[0], 'r')
 readFile()
</code></pre>

blocks|key|3557777|text|在我的例子中，lxml解决了这个问题。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3557778|from+lxml+import+etree

for+_,+elein+etree.iterparse(xml_file,+tag='tag_i_wanted',+unicode='utf-8'):
++++print(ele.tag,+ele.text)++|code-block|syntax|javascript|3557779|在另一种情况下，|3557780|parser+=+etree.XMLParser(recover=True)
tree+=+etree.parse(xml_file,+parser=parser)
tags_needed+=+tree.iter('TAG+NAME')|3557781|感谢theeastcoastwest|offset|length|3557782|Python+2.7|3557783|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/54228063/1693901^0|0|0|0|0|2|G|0|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|10|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|11|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|12|8|@]|9|@$M|13|N|14|1|15]]|A|$]]|$1|O|3|P|5|6|7|16|8|@]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|17|8|@]|9|@]|A|$]]]|R|$S|$5|T|U|V|A|$W|X]]]]

lxml solved the issue, in my case

<pre><code>from lxml import etree

for _, elein etree.iterparse(xml_file, tag='tag_i_wanted', unicode='utf-8'):
 print(ele.tag, ele.text) 
</code></pre>

in another case,

<pre><code>parser = etree.XMLParser(recover=True)
tree = etree.parse(xml_file, parser=parser)
tags_needed = tree.iter('TAG NAME')
</code></pre>

Thanks to <a href="https://stackoverflow.com/a/54228063/1693901">theeastcoastwest</a>

Python 2.7

blocks|key|5287180|text|我在这里尝试了答案中的其他解决方案，但没有运气。因为我只需要从单个xml节点提取值，所以我放弃了，并编写了我的函数来执行此操作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5287181|def+ParseXmlTagContents(source,+tag,+tagContentsRegex):
++++openTagString+=+"<"%2Btag%2B">"
++++closeTagString+=+"</"%2Btag%2B">"
++++found+=+re.search(openTagString+%2B+tagContentsRegex+%2B+closeTagString,+source)
++++if+found:+++
++++++++start+=+found.regs[0][0]
++++++++end+=+found.regs[0][1]
++++++++return+source[start%2Blen(openTagString):end-len(closeTagString)]
++++return+""|code-block|syntax|javascript|5287182|示例用法如下：|5287183|<?xml+version="1.0"+encoding="utf-16"?>
<parentNode>
++++<childNode>123</childNode>
</parentNode>

ParseXmlTagContents(xmlString,+"childNode",+"[0-9]%2B")|5287184|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

I tried the other solutions in the answers here but had no luck. Since I only needed to extract the value from a single xml node I gave in and wrote my function to do so:

<pre><code>def ParseXmlTagContents(source, tag, tagContentsRegex):
 openTagString = "&lt;"+tag+"&gt;"
 closeTagString = "&lt;/"+tag+"&gt;"
 found = re.search(openTagString + tagContentsRegex + closeTagString, source)
 if found: 
 start = found.regs[0][0]
 end = found.regs[0][1]
 return source[start+len(openTagString):end-len(closeTagString)]
 return ""
</code></pre>

Example usage would be:

<pre><code>&lt;?xml version="1.0" encoding="utf-16"?&gt;
&lt;parentNode&gt;
 &lt;childNode&gt;123&lt;/childNode&gt;
&lt;/parentNode&gt;

ParseXmlTagContents(xmlString, "childNode", "[0-9]+")
</code></pre>

I receive xml strings from an external source that can contains unsanitized user contributed content.

The following xml string gave a ParseError in <code>cElementTree</code>:

<pre><code>&gt;&gt;&gt; print repr(s)
'&lt;Comment&gt;dddddddd\x08\x08\x08\x08\x08\x08_____&lt;/Comment&gt;'
&gt;&gt;&gt; import xml.etree.cElementTree as ET
&gt;&gt;&gt; ET.XML(s)

Traceback (most recent call last):
 File "&lt;pyshell#4&gt;", line 1, in &lt;module&gt;
 ET.XML(s)
 File "&lt;string&gt;", line 106, in XML
ParseError: not well-formed (invalid token): line 1, column 17
</code></pre>

Is there a way to make cElementTree not complain?

ParseError: not well-formed (invalid token) using cElementTree

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我从外部源接收xml字符串，该外部源可能包含未清理的用户贡献的内容。下面的xml字符串在cElementTree中提供了一个ParseError>>> print repr(s)'<Comment>dddddddd\x08\x08\x08\x08\x08\x08_____</Comment>'>>> import xml.etree.cElementTree as ET>>> ET.XML(s)T

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