如何从联系人框架中检索电话号码

Question

尝试检索移动电话号码的联系人新手。我有地址，名字，电子邮件，但不能识别手机。这就是我得到的。标有**的部分就是我出错的地方。

if let oldContact = self.contactItem {
    let store = CNContactStore()

    do {
        let mykeysToFetch = [CNContactFormatter.descriptorForRequiredKeysForStyle(.FullName), CNContactEmailAddressesKey, CNContactPostalAddressesKey,CNContactImageDataKey, CNContactImageDataAvailableKey,CNContactPhoneNumbersKey]
        let contact = try store.unifiedContactWithIdentifier(oldContact.identifier, keysToFetch: mykeysToFetch)

        dispatch_async(dispatch_get_main_queue(), { () -> Void in
            if contact.imageDataAvailable {
                if let data = contact.imageData {
                    self.contactImage.image = UIImage(data: data)
                }
            }

            self.fullName.text = CNContactFormatter().stringFromContact(contact)
            self.email.text = contact.emailAddresses.first?.value as? String
            self.phoneNumber.text = contact.phoneNumbers.first?.value as? String

            **if contact.isKeyAvailable(CNContactPhoneNumbersKey){
                if let phoneNum = contact.phoneNumbers.first?.value as? String {
                    self.phoneNumber.text = phoneNum as String
                }

            }**

            if contact.isKeyAvailable(CNContactPostalAddressesKey) {
                if let postalAddress = contact.postalAddresses.first?.value as? CNPostalAddress {
                    self.address.text = CNPostalAddressFormatter().stringFromPostalAddress(postalAddress)
                } else {
                    self.address.text = "No Address"
                }
            }
        })
    } catch {
        print(error)
    }
}

Answer 1

如果您想要联系人的移动电话列表，可以查看phoneNumbers，它是一个CNLabeledValue数组，并找到label为CNLabelPhoneNumberMobile或CNLabelPhoneNumberiPhone的移动电话。

例如，您可以这样做：

let mobilePhoneLabels = Set<String>(arrayLiteral: CNLabelPhoneNumberMobile, CNLabelPhoneNumberiPhone, "cell", "mobile") // use whatever you want here; you might want to include a few strings like shown here to catch any common custom permutations user may have used

let mobileNumbers = contact.phoneNumbers.filter { mobilePhoneLabels.contains($0.label) && $0.value is CNPhoneNumber }
    .map { ($0.value as! CNPhoneNumber).stringValue }

所以如果你想要第一个：

let mobileNumber = mobileNumbers.first ?? ""   // or use `if let` syntax

或者，如果您想要它们列表的字符串表示形式：

let mobileNumberString = mobileNumbers.joinWithSeparator(" ; ")

如何处理这一组手机号码取决于您，但希望这说明了基本思想。