无法使LibXL xlSheetGetNamedRange正常工作

Question

我正在尝试和LibXL一起工作。我可以从工作表中提取数据，但需要一个函数来将具有Excel行和列索引的字符串转换为startRow、endRow、startCol、endCol。

"A1:B3“到startRow = 0，endRow = 2，startCol = 0，endCol =1 (LibXL使用基于0的索引)

我已经试过我能想到的一切了。该库没有任何使用此函数的示例，并且文档非常稀疏。我做错了什么？

下面是我的代码：

int main()
{
    const char range[] = "B2:C3";
    int i, ret, rowFirst=0, rowLast=0, colFirst=0, colLast=0;
    BookHandle book;
    SheetHandle sheet;

    book = xlCreateBook();

    ret = xlBookLoad(book, "/home/jason/Downloads/panel.xls");

    sheet = xlBookGetSheet(book, 0);

    ret = xlSheetGetNamedRange(sheet, &range[0], &rowFirst, &rowLast, &colFirst, &colLast);

    printf("ret from xlSheet...Range = %d\n", ret);

    printf("%s\n", xlBookErrorMessage(book));
    printf("rowLast = %d\n", rowLast);
    printf("rowLast = %d\n", rowLast);
    printf("colFirst = %d\n", colFirst);
    printf("colLast = %d\n", colLast);

    return 0;

}

Answer 1

使用xlSheetAddrToRowCol()函数实现此目的：

int rowStart, colStart, rowEnd, colEnd;
int rowRelativeStart, colRelativeStart, rowRelativeEnd, colRelativeEnd;

xlSheetAddrToRowCol(sheet, "B2", &rowStart, &colStart, &rowRelativeStart, &colRelativeStart);
xlSheetAddrToRowCol(sheet, "C3", &rowEnd, &colEnd, &rowRelativeEnd, &colRelativeEnd);