使用Regex清除font-size标签

Question

我尝试使用正则表达式将<font style="font-size:85%;font-family:arial,sans-serif">从

font-size:85%;

我的正则表达式是^font-size:(*);

我的意思是我必须完全删除font-size标签。

有谁能帮帮我吗？

谢谢!

Answer 1

当前正则表达式的几个方面会导致它失败：

^font-size:(*);

您将锚定到行^的开头-属性不在行的开头。

*本身没有任何意义。

将其更改为：

font-size: ?\d{1,2}%;

Answer 2

这是您需要的正则表达式：

string html = @"<font style=""font-size:85%;font-family:arial,sans-serif"">";
string pattern = @"font-size\s*?:.*?(;|(?=""|'|;))";
string cleanedHtml = Regex.Replace(html, pattern, string.Empty);

即使在pt或em中定义了font-size，或者定义了一组不同的样式(即，.未指定font-family )。您可以查看结果。

正则表达式的解释如下：

// font-size\s*?:.*?(;|(?="|'|;))
// 
// Match the characters “font-size” literally «font-size»
// Match a single character that is a “whitespace character” (spaces, tabs, and line breaks) «\s*?»
//    Between zero and unlimited times, as few times as possible, expanding as needed (lazy) «*?»
// Match the character “:” literally «:»
// Match any single character that is not a line break character «.*?»
//    Between zero and unlimited times, as few times as possible, expanding as needed (lazy) «*?»
// Match the regular expression below and capture its match into backreference number 1 «(;|(?="|'|;))»
//    Match either the regular expression below (attempting the next alternative only if this one fails) «;»
//       Match the character “;” literally «;»
//    Or match regular expression number 2 below (the entire group fails if this one fails to match) «(?="|'|;)»
//       Assert that the regex below can be matched, starting at this position (positive lookahead) «(?="|'|;)»
//          Match either the regular expression below (attempting the next alternative only if this one fails) «"»
//             Match the character “"” literally «"»
//          Or match regular expression number 2 below (attempting the next alternative only if this one fails) «'»
//             Match the character “'” literally «'»
//          Or match regular expression number 3 below (the entire group fails if this one fails to match) «;»
//             Match the character “;” literally «;»