Java - CardLayout show() IllegalArgumentException

Question

我有一个关于CardLayout显示方法的问题

所以我声明了我的CardLayout并将它应用于我的JPanel

CardLayout cl = new CardLayout();
panel.setLayout(cl);

然后我在CardLayout中添加了2个面板

cl.addLayoutComponent(panel, "menuScreen");
cl.addLayoutComponent(panel1, "gameScreen");

然后，我有一个JButton，当单击它时，我会显示该gameScreen

public void mouseClicked(MouseEvent e) {
    if(e.getSource() ==  (startGame))

    scenechange.show(panel,"gameScreen");
}

唯一的问题是它不能进入我的gameScreen。它给了我一个llegalArgumentException。它显示“线程中出现异常"AWT-EventQueue-0”java.lang.IllegalArgumentException: CardLayout的父级错误“。

提前感谢

Answer 1

您需要有三个面板。家长和两张卡片。

当前，您有"panel“作为父级和子级之一。

CardLayout cl = new CardLayout();
panel.setLayout(cl);

和

cl.addLayoutComponent(panel, "menuScreen");

考虑Java trail中的以下代码示例

 ....
 //Create the "cards".
    JPanel card1 = new JPanel();
    card1.add(new JButton("Button 1"));

    JPanel card2 = new JPanel();
    card2.add(new JTextField("TextField", 20));

    //Create the panel that contains the "cards".
    cards = new JPanel(new CardLayout());
    cards.add(card1, BUTTONPANEL);
    cards.add(card2, TEXTPANEL);