我使用akka已经有一段时间了。我开始在我的代码中看到一些模式来解决异步回复的延迟问题。这个实现可以吗?还有另一种不阻塞的延迟回复的方法吗?
class ApplicationApi(asyncIo : ActorRef) extends Actor {
// store senders to late reply
val waiting = Map[request, ActorRef]()
def receive = {
// an actore request for a user, store it to late reply and ask for asyncIo actor to do the real job
case request : GetUser =>
waiting += (sender -> request)
asyncIo ! AsyncGet("http://app/user/" + request.userId)
// asyncio response, parse and reply
case response : AsyncResponse =>
val user = parseUser(response.body)
waiting.remove(response.request) match {
case Some(actor) => actor ! GetUserResponse(user)
}
}
}发布于 2012-08-24 00:20:01
在等待回复时避免阻塞的一种方法是使用ask方法发送。?运算符-返回Future (与返回()的!不同)。
使用onSuccess或foreach方法,您可以指定在将来完成回复时要执行的操作。要使用此特性,您需要混合使用AskSupport特征:
class ApplicationApi(asyncIo : ActorRef) extends Actor with AskSupport {
def receive = {
case request: GetUser =>
val replyTo = sender
asyncIo ? AsyncGet("http://app/user/" + request.userId) onSuccess {
case response: AsyncResponse =>
val user = parseUser(response.body)
replyTo ! GetUserResponse(user)
}
}避免使用此技术执行任何修改ApplicationApi执行元状态的副作用,因为该效果将与接收循环不同步地发生。不过,向其他参与者转发消息应该是安全的。
顺便说一句,这里有一个技巧可以捕获当前的sender作为模式匹配的一部分,避免以后将其赋值给变量。
trait FromSupport { this: Actor =>
case object from {
def unapply(msg: Any) = Some(msg, sender)
}
}
class MyActor extends Actor with FromSupport {
def receive = {
case (request: GetUser) from sender =>
// sender is now a variable (shadowing the method) that is safe to use in a closure
}
}https://stackoverflow.com/questions/12095328
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