带有where子句的Mysql透视表

Question

select student_id, class_id, section_id, exam_date, exam_id, 
       sum(number*(1-abs(sign(subject-1)))) as sub1, 
       sum(number*(1-abs(sign(subject-2)))) as sub2, 
       sum(number*(1-abs(sign(subject-3)))) as sub3, 
       sum(number*(1-abs(sign(subject-4)))) as sub4, 
       sum(number*(1-abs(sign(subject-5)))) as sub5, 
       sum(number*(1-abs(sign(subject-6)))) as sub6 
from result 
where class_id = '7' and section id = '3' and YEAR(exam_date) = '2012' and exam_id = '3'
GROUP BY student_id

我有一个问题，当我用where子句过滤时，所有的数值都是0，如果我运行不带where子句的查询，结果将是好的，但来自所有数据库。如何使用where子句过滤查询？有人能帮我吗？

Answer 1

您还需要按class_id分组

SELECT * FROM ( 
select student_id, class_id,  
       sum(number*(1-abs(sign(subject-1)))) as sub1,  
       sum(number*(1-abs(sign(subject-2)))) as sub2,  
       sum(number*(1-abs(sign(subject-3)))) as sub3,  
       sum(number*(1-abs(sign(subject-4)))) as sub4,  
       sum(number*(1-abs(sign(subject-5)))) as sub5,  
       sum(number*(1-abs(sign(subject-6)))) as sub6  
from result GROUP BY student_id,class_id) m 
where class_id = '7'

Answer 2

将查询放在where之前。

SELECT * FROM (
select student_id, class_id, 
       sum(number*(1-abs(sign(subject-1)))) as sub1, 
       sum(number*(1-abs(sign(subject-2)))) as sub2, 
       sum(number*(1-abs(sign(subject-3)))) as sub3, 
       sum(number*(1-abs(sign(subject-4)))) as sub4, 
       sum(number*(1-abs(sign(subject-5)))) as sub5, 
       sum(number*(1-abs(sign(subject-6)))) as sub6 
from result GROUP BY student_id) m
where class_id = '7'