blocks|key|3838285|text|new+Date('2012.08.10').getTime()+/+1000|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3838286|检查JavaScript+Date+documentation。|unstyled|offset|length|3838287|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Date^0|0|2|T|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|R|8|@]|9|@$G|S|H|T|1|U]]|A|$]]|$1|I|3|-4|5|F|7|V|8|@]|9|@]|A|$]]]|J|$K|$5|L|M|N|A|$O|P]]]]

<pre><code>new Date('2012.08.10').getTime() / 1000
</code></pre>

Check the <a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Date" rel="noreferrer">JavaScript Date documentation</a>.

blocks|key|3838320|text|parseInt((new+Date('2012.08.10').getTime()+/+1000).toFixed(0))|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3838321|重要的是要添加toFixed(0)，以便在除以1000时删除任何小数，以便将毫秒转换为秒。|unstyled|offset|length|style|CODE|3838322|.getTime()函数以毫秒为单位返回时间戳，但真正的unix时间戳始终以秒为单位。|3838323|entityMap^0|0|7|A|0|0|A|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|P|8|@$G|Q|H|R|I|J]]|9|@]|A|$]]|$1|K|3|L|5|F|7|S|8|@$G|T|H|U|I|J]]|9|@]|A|$]]|$1|M|3|-4|5|F|7|V|8|@]|9|@]|A|$]]]|N|$]]

<pre><code>parseInt((new Date('2012.08.10').getTime() / 1000).toFixed(0))
</code></pre>

It's important to add the <code>toFixed(0)</code> to remove any decimals when dividing by 1000 to convert from milliseconds to seconds. 

The <code>.getTime()</code> function returns the timestamp in milliseconds, but true unix timestamps are always in seconds.

blocks|key|2155285|text|​|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2155286|var+d+=+'2016-01-01T00:00:00.000Z';
console.log(new+Date(d).valueOf());+//+returns+the+number+of+milliseconds+since+the+epoch|code-block|syntax|javascript|2155287|2155288|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|J|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|K|8|@]|9|@]|A|$E|F]]|$1|G|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|H|3|-4|5|6|7|M|8|@]|9|@]|A|$]]]|I|$]]

<div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>var d = '2016-01-01T00:00:00.000Z';
console.log(new Date(d).valueOf()); // returns the number of milliseconds since the epoch</code></pre>
</div>
</div>

blocks|key|2155280|text|你应该看看moment.js的应用程序接口，它非常容易使用，并且有很多内置的功能。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2155281|我认为对于你的问题，你可以使用这样的东西：|2155282|var+unixTimestamp+=+moment('2012.08.10',+'YYYY.MM.DD').unix();|code-block|syntax|javascript|2155283|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

You should check out the moment.js api, it is very easy to use and has lots of built in features.

I think for your problem, you could use something like this:

<pre><code>var unixTimestamp = moment('2012.08.10', 'YYYY.MM.DD').unix();
</code></pre>

blocks|key|2155427|text|var+date+=+new+Date('2012.08.10');
var+unixTimeStamp+=+Math.floor(date.getTime()+/+1000);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|2155428|在这种情况下，重要的是只返回一个整数(所以简单的除法是行不通的)，并且只返回实际经过的秒数(这就是为什么此代码使用Math.floor()而不是Math.round())。|unstyled|offset|length|style|CODE|2155429|entityMap^0|0|1L|C|20|C|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|N|8|@$G|O|H|P|I|J]|$G|Q|H|R|I|J]]|9|@]|A|$]]|$1|K|3|-4|5|F|7|S|8|@]|9|@]|A|$]]]|L|$]]

<pre><code>var date = new Date('2012.08.10');
var unixTimeStamp = Math.floor(date.getTime() / 1000);
</code></pre>

In this case it's important to return only a whole number (so a simple division won't do), and also to only return actually elapsed seconds (that's why this code uses <code>Math.floor()</code> and not <code>Math.round()</code>).

blocks|key|2155358|text|您可以简单地使用一元%2B运算符|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2155359|(%2Bnew+Date('2012.08.10')/1000).toFixed(0);|offset|length|style|CODE|2155360|http://xkr.us/articles/javascript/unary-add/+-在Dates下查找。|2155361|entityMap|0|LINK|mutability|MUTABLE|url|http://xkr.us/articles/javascript/unary-add/^0|0|0|16|0|0|18|0|0^^$0|@$1|2|3|4|5|6|7|R|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|S|8|@$D|T|E|U|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|V|8|@]|9|@$D|W|E|X|1|Y]]|A|$]]|$1|J|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|K|$L|$5|M|N|O|A|$P|Q]]]]

You could simply use the unary + operator

<code>(+new Date('2012.08.10')/1000).toFixed(0);</code>

<a href="http://xkr.us/articles/javascript/unary-add/" rel="noreferrer">http://xkr.us/articles/javascript/unary-add/</a> - look under Dates.

blocks|key|2155331|text|您可以使用Date.parse()，但它接受的输入格式依赖于实现。但是，如果您可以将日期转换为YYYY格式(YYYY+DD)，那么大多数实现都应该能够理解它。|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|2155332|参见Why+does+Date.parse+give+incorrect+results?。|2155333|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/2587345/javascript-date-parse^0|5|C|0|2|17|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@$9|Q|A|R|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|S|8|@]|D|@$9|T|A|U|1|V]]|E|$]]|$1|H|3|-4|5|6|7|W|8|@]|D|@]|E|$]]]|I|$J|$5|K|L|M|E|$N|O]]]]

You can use Date.parse(), but the input formats that it accepts are implementation-dependent. However, if you can convert the date to ISO format (YYYY-MM-DD), most implementations should understand it.

See <a href="https://stackoverflow.com/questions/2587345/javascript-date-parse">Why does Date.parse give incorrect results?</a>.

blocks|key|2202877|text|您可以使用Date.parse()方法完成此操作。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2202878|Date.parse($("#yourCustomDate).val())|code-block|syntax|javascript|2202879|Date.parse("03.03.2016")输出->+1456959600000|2202880|Date.parse("2015-12-12")输出->+1449878400000|2202881|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

You can do it using Date.parse() Method.

<pre><code>Date.parse($("#yourCustomDate).val())
</code></pre>

Date.parse("03.03.2016")
output-> 1456959600000

Date.parse("2015-12-12")
output-> 1449878400000

blocks|key|2202728|text|var+datestr+=+'2012.08.10';
var+timestamp+=+(new+Date(datestr.split(".").join("-")).getTime())/1000;|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|2202729|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>var datestr = '2012.08.10';
var timestamp = (new Date(datestr.split(".").join("-")).getTime())/1000;
</code></pre>

blocks|key|3838415|text|在将时间戳与PHP中的时间戳进行比较后，上面的时间戳似乎都不适合我的时区。下面的代码给了我与PHP相同的结果，这对我正在做的项目来说是最重要的。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3838416|​|3838417|function+getTimeStamp(input)+{
++++var+parts+=+input.trim().split('+');
++++var+date+=+parts[0].split('-');
	var+time+=+(parts[1]+?+parts[1]+:+'00:00:00').split(':');

	//+NOTE::+Month:+0+=+January+-+11+=+December.
	var+d+=+new+Date(date[0],date[1]-1,date[2],time[0],time[1],time[2]);
	return+d.getTime()+/+1000;
}

//+USAGE::
var+start+=+getTimeStamp('2017-08-10');
var+end+=+getTimeStamp('2017-08-10+23:59:59');

console.log(start+%2B+'+-+'+%2B+end);|code-block|syntax|javascript|3838418|3838419|我在NodeJS上使用这个，我们的时区是‘澳大利亚/悉尼’。因此，我不得不在.env文件中添加以下内容：|3838420|TZ+=+'Australia/Sydney'|3838421|上面的等同于：|3838422|process.env.TZ+=+'Australia/Sydney'|3838423|entityMap^0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|T|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|U|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|V|8|@]|9|@]|A|$G|H]]|$1|I|3|C|5|6|7|W|8|@]|9|@]|A|$]]|$1|J|3|K|5|6|7|X|8|@]|9|@]|A|$]]|$1|L|3|M|5|F|7|Y|8|@]|9|@]|A|$G|H]]|$1|N|3|O|5|6|7|Z|8|@]|9|@]|A|$]]|$1|P|3|Q|5|F|7|10|8|@]|9|@]|A|$G|H]]|$1|R|3|-4|5|6|7|11|8|@]|9|@]|A|$]]]|S|$]]

After comparing timestamp with the one from PHP, none of the above seems correct for my timezone. The code below gave me same result as PHP which is most important for the project I am doing.

<div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>function getTimeStamp(input) {
 var parts = input.trim().split(' ');
 var date = parts[0].split('-');
	var time = (parts[1] ? parts[1] : '00:00:00').split(':');

	// NOTE:: Month: 0 = January - 11 = December.
	var d = new Date(date[0],date[1]-1,date[2],time[0],time[1],time[2]);
	return d.getTime() / 1000;
}

// USAGE::
var start = getTimeStamp('2017-08-10');
var end = getTimeStamp('2017-08-10 23:59:59');

console.log(start + ' - ' + end);</code></pre>
</div>
</div>


I am using this on NodeJS, and we have timezone 'Australia/Sydney'. So, I had to add this on .env file:

<pre><code>TZ = 'Australia/Sydney'
</code></pre>

Above is equivalent to:

<pre><code>process.env.TZ = 'Australia/Sydney'
</code></pre>

blocks|key|3928596|text|将时间戳转换为unix时间戳。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3928597|const+date+=+1513787412;+const+unixDate+=+new+Date(date+*+1000);//+Dec+20+2020+(object)|offset|length|style|CODE|3928598|获取转换后的const+TimeStamp+=+new+Date(date*1000).getTime();+//1513787412000的timeStamp|3928599|entityMap^0|0|0|2F|0|6|1S|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|M|8|@$D|N|E|O|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|P|8|@$D|Q|E|R|F|G]]|9|@]|A|$]]|$1|J|3|-4|5|6|7|S|8|@]|9|@]|A|$]]]|K|$]]

convert timestamp to unix timestamp.

<code>const date = 1513787412;
const unixDate = new Date(date * 1000);// Dec 20 2020 (object)</code>

to get the timeStamp after conversion 
<code>const TimeStamp = new Date(date*1000).getTime(); //1513787412000</code>

How can I convert normal date <code>2012.08.10</code> to unix timestamp in javascript?

Fiddle: <a href="http://jsfiddle.net/J2pWj/" rel="noreferrer">http://jsfiddle.net/J2pWj/</a>
 
 
 
 
 
I've seen many posts here that convert it in PHP, Ruby, etc... But I need to do this inside JS.

Convert normal date to unix timestamp

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

文章

问答

视频

教程

学习中心

腾讯云实验室

直播

竞赛

腾讯云代码分析专区

腾讯iOA零信任安全管理系统专区

腾讯云架构师技术同盟交流圈

腾讯云数据库专区

腾讯云智能顾问专区

腾讯云原生专区

腾讯混元专区

腾讯云TCE专区

腾讯云Lighthouse专区

腾讯云HAI专区

腾讯云Edgeone专区

腾讯云存储专区

腾讯云智能专区

腾讯轻联专区 

腾讯云开发专区

TAPD专区

腾讯轻量云游戏服专区

EdgeOne AI 安全实战专区

腾讯云最具价值专家

腾讯云架构师技术同盟

腾讯云创作之星

腾讯云开发者先锋

腾讯云代码助手

云原生构建

TAPD 敏捷项目管理

Cloud Studio

SDK中心

API中心

命令行工具

涵盖代码开发、场景应用、自动测试全流程，助你从零构建专属AI助手

一站式MCP教程库，解锁AI应用新玩法

聚焦“写作效率、视觉美观与运行性能”三方面进行全面升级，为您提供更高效、稳定的创作环境

社区富文本&Markdown编辑器全新改版上线，欢迎大家体验!

诚挚邀请您参与本次调研，分享您的真实使用感受与建议。您的反馈至关重要，感谢您的支持与参与！

社区新版编辑器体验调研

如何在javascript中将普通日期2012.08.10转换为unix时间戳？小提琴：我在这里看到过很多把它转换成PHP、Ruby等的帖子。但我需要在JS中执行此操作。

问将普通日期转换为unix时间戳
EN

回答 11

Stack Overflow用户

Stack Overflow用户

Stack Overflow用户

社区

活动

圈层

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问将普通日期转换为unix时间戳EN

回答 11

Stack Overflow用户

Stack Overflow用户

Stack Overflow用户

社区

活动

圈层

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问将普通日期转换为unix时间戳
EN