我正在尝试获取基于角色的munus和子菜单(在其他表中指定)。基于角色,例如。如果我选择MenuID: 1,2,5,我应该会得到M1,M2和M3的所有子菜单。MenuParentID指定父级的MenuId。
MenuID MenuParentID MenuName MenuNavigateUrl HasSubMenus
1 -1 M1 1.aspx 0
2 -1 M2 # 1
3 2 M2.1 2.aspx 0
4 2 M2.2 3.aspx 0
5 -1 M3 # 1
6 5 M3.1 # 1
7 5 M3.2 # 1
8 6 M3.1.1 4.aspx 0
9 6 M3.1.2 5.aspx 0
10 7 M3.2.1 6.aspx 0
11 7 M3.2.2 7.aspx 0
12 -1 M4 # 1
13 12 M4.1 8.aspx 0
14 12 M4.2 9.aspx 0 下面是我所做的:
DELIMITER $$
DROP FUNCTION IF EXISTS `myDB`.`GetPermissions`$$
CREATE DEFINER=`root`@`%` FUNCTION `GetPermissions`(
rootMenuID int(11)
) RETURNS varchar(200) CHARSET latin1
BEGIN
DECLARE menuIdList VARCHAR(100);
DECLARE menu_id INT(11);
DECLARE record_not_found INT DEFAULT 0;
DECLARE getMenuCursor CURSOR FOR SELECT DISTINCT(MenuId) FROM MenuIdListTable;
DECLARE CONTINUE HANDLER FOR NOT FOUND SET record_not_found = 1;
CREATE TEMPORARY TABLE MenuIdListTable(MenuId INT(11) NULL);
SET menuIdList = ',';
IF((SELECT COUNT(*) FROM menus WHERE MenuParentID = rootMenuID) > 0) THEN
INSERT INTO MenuIdListTable(MenuID) SELECT MenuID FROM menus WHERE
MenuParentID = rootMenuID;
OPEN getMenuCursor;
read_loop: LOOP
FETCH getMenuCursor INTO menu_id;
IF record_not_found THEN
LEAVE read_loop;
END IF;
SET menuIdList = CONCAT(menuIdList,menu_id,',');
END LOOP read_loop;
END IF;
DROP TEMPORARY TABLE MenuIdListTable;
SET menuIdList = SUBSTR(menuIdList,1,LENGTH(menuIdList)-1);
RETURN menuIdList;
END$$
DELIMITER ;但是我不能应用递归逻辑来获取所有子菜单。例如。对于'M3‘(MenuID = 5),我得到了子菜单'M3.1’和'M3.2';但没有得到它们的子菜单。即'M3.1':'M3.1.1','M3.1.2‘;'M3.2':'M3.2.1','M3.2.2’。另外,如果它们中的一个有子菜单,问题将继续存在!请帮帮忙。
发布于 2012-08-04 19:27:30
尝试以下代码:
DROP TABLE IF EXISTS temp;
CREATE TABLE temp(id int,MenuID int,MenuName varchar(50),MenuParentID int,HasSubMenus int) SELECT (@id:=@id+1) as id,MenuID,MenuName,MenuParentID,HasSubMenus from menus,
(SELECT @id:=0) id where MenuParentID = 5;
select * from temp;
DROP TABLE IF EXISTS output;
CREATE TABLE output(MenuID int,MenuName varchar(50),MenuParentID int,HasSubMenus int) select MenuID,MenuName,MenuParentID,HasSubMenus from temp;
SET @idmin = (SELECT min(id) from temp);
SET @idmax = (SELECT max(id) from temp);
WHILE @idmin <= @idmax DO
INSERT INTO output(MenuID,MenuName,MenuParentID,HasSubMenus)
select MenuID,MenuName,MenuParentID,HasSubMenus from menus where MenuParentID=(select MenuID from temp where id = @idmin);
SET @idmin=@idmin+1;
END WHILE;
select (@id:=@id) as id1,GROUP_CONCAT(MenuName,',') from output, (SELECT @id:=1) id1 group by id1;发布于 2012-08-04 15:37:24
plsql或CTE的plsql或CTE的“优先连接”的joy,错过了mysql。
因为我的大脑目前没有能力完全解析你给定的mysql函数,它只是抛出一个引用:http://explainextended.com/2009/03/17/hierarchical-queries-in-mysql/它会给你一些好的解释(有时是邪恶的……就像只在一个select中的树结构一样)关于mysql中的层次结构
https://stackoverflow.com/questions/11806542
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