jQuery切换(单击以显示一个div，而隐藏其他div)

Question

基本思想是我有一堆div，每个div都可以切换(显示/隐藏)。

当切换一个div时，我希望将当前显示的其他div隐藏起来，这样一次只允许显示一个div。

此外，我希望能够在元素外部单击以隐藏打开的div。

为了让事情更清楚，我提供了一个示例，它目前可以做我想做的所有事情，除了在打开一个div时关闭另一个div (一次只打开一个div的功能)：

​

$(document).ready(function(){

  $('div.dropdown').each(function() {
    var $dropdown = $(this);

    $("a.dropdown-link", $dropdown).click(function(e) {
      e.preventDefault();
      $("div.dropdown-container", $dropdown).toggle();
      return false;
    });

});
    
  $('html').click(function(){
    $("div.dropdown-container").hide();
  });
     
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>
<div id="dropdown-1" class="dropdown dropdown-processed">
  <a class="dropdown-link" href="#">Options</a>
  <div class="dropdown-container" style="display: none;">
    <ul>
      <li>Item 1</li>
      <li>Item 2</li>
      <li>Item 3</li>
    </ul>
  </div>
</div>

<div id="dropdown-2" class="dropdown dropdown-processed">
  <a class="dropdown-link" href="#">Options</a>
  <div class="dropdown-container" style="display: none;">
    <ul>
      <li>Item 1</li>
      <li>Item 2</li>
      <li>Item 3</li>
    </ul>
  </div>
</div>

<div id="dropdown-3" class="dropdown dropdown-processed">
  <a class="dropdown-link" href="#">Options</a>
  <div class="dropdown-container" style="display: none;">
    <ul>
      <li>Item 1</li>
      <li>Item 2</li>
      <li>Item 3</li>
    </ul>
  </div>
</div>

​

Answer 1

你基本上只需要隐藏所有的div，除了被切换的那个：

​

$(document).ready(function(){

  $('div.dropdown').each(function() {
    var $dropdown = $(this);

    $("a.dropdown-link", $dropdown).click(function(e) {
      e.preventDefault();
      $div = $("div.dropdown-container", $dropdown);
      $div.toggle();
      $("div.dropdown-container").not($div).hide();
      return false;
    });

});
    
  $('html').click(function(){
    $("div.dropdown-container").hide();
  });
     
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>
<div id="dropdown-1" class="dropdown dropdown-processed">
  <a class="dropdown-link" href="#">Options</a>
  <div class="dropdown-container" style="display: none;">
    <ul>
      <li>Item 1</li>
      <li>Item 2</li>
      <li>Item 3</li>
    </ul>
  </div>
</div>

<div id="dropdown-2" class="dropdown dropdown-processed">
  <a class="dropdown-link" href="#">Options</a>
  <div class="dropdown-container" style="display: none;">
    <ul>
      <li>Item 1</li>
      <li>Item 2</li>
      <li>Item 3</li>
    </ul>
  </div>
</div>

<div id="dropdown-3" class="dropdown dropdown-processed">
  <a class="dropdown-link" href="#">Options</a>
  <div class="dropdown-container" style="display: none;">
    <ul>
      <li>Item 1</li>
      <li>Item 2</li>
      <li>Item 3</li>
    </ul>
  </div>
</div>

​

Answer 2

您可以使用以下代码，通过智能和简单的方式来实现：

<div id="dropdown-1" class="dropdown dropdown-processed">
  <a class="dropdown-link" href="#">Options</a>
  <div class="dropdown-container" style="display: none;">
    <ul>
      <li>Item 1</li>
      <li>Item 2</li>
      <li>Item 3</li>
    </ul>
  </div>
</div>

<div id="dropdown-2" class="dropdown dropdown-processed">
  <a class="dropdown-link" href="#">Options</a>
  <div class="dropdown-container" style="display: none;">
    <ul>
      <li>Item 1</li>
      <li>Item 2</li>
      <li>Item 3</li>
    </ul>
  </div>
</div>

<div id="dropdown-3" class="dropdown dropdown-processed">
  <a class="dropdown-link" href="#">Options</a>
  <div class="dropdown-container" style="display: none;">
    <ul>
      <li>Item 1</li>
      <li>Item 2</li>
      <li>Item 3</li>
    </ul>
  </div>
</div>

​

$(document).ready(function(){

 $(".dropdown-link").click(function(){
 $(".dropdown-container").slideUp('slow')
 $(this).closest('.dropdown').find('.dropdown-container').slideDown('slow');
 
 });

});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="dropdown-1" class="dropdown dropdown-processed">
  <a class="dropdown-link" href="#">Options</a>
  <div class="dropdown-container" style="display: none;">
    <ul>
      <li>Item 1</li>
      <li>Item 2</li>
      <li>Item 3</li>
    </ul>
  </div>
</div>

<div id="dropdown-2" class="dropdown dropdown-processed">
  <a class="dropdown-link" href="#">Options</a>
  <div class="dropdown-container" style="display: none;">
    <ul>
      <li>Item 1</li>
      <li>Item 2</li>
      <li>Item 3</li>
    </ul>
  </div>
</div>

<div id="dropdown-3" class="dropdown dropdown-processed">
  <a class="dropdown-link" href="#">Options</a>
  <div class="dropdown-container" style="display: none;">
    <ul>
      <li>Item 1</li>
      <li>Item 2</li>
      <li>Item 3</li>
    </ul>
  </div>
</div>

​

工作示例链接：http://jsfiddle.net/NFTFw/1901/

Answer 3

尝试以下操作：

$(document).ready(function(){

  $("a.dropdown-link").click(function(e) {
    e.preventDefault();
    var $div = $(this).next('.dropdown-container');
    $(".dropdown-container").not($div).hide();
    if ($div.is(":visible")) {
        $div.hide()
    }  else {
       $div.show();
    }
});

   $(document).click(function(e){
       var p = $(e.target).closest('.dropdown').length
       if (!p) {
          $(".dropdown-container").hide();
       }
   });

});

DEMO