sprintf的Python等效项

Question

有没有人有一个很好的技巧，如何将PHP函数移植到python？

/**
 * converts id (media id) to the corresponding folder in the data-storage
 * eg: default mp3 file with id 120105 is stored in
 * /(storage root)/12/105/default.mp3
 * if absolute paths are needed give path for $base
 */

public static function id_to_location($id, $base = FALSE)
{
    $idl = sprintf("%012s",$id);
    return $base . (int)substr ($idl,0,4) . '/'. (int)substr($idl,4,4) . '/' . (int)substr ($idl,8,4);
}

Answer 1

在一行代码(Python 2.x)中：

id_to_location = lambda i: '/%d/%d/%d/' % (int(i)/1e8, int(i)%1e8/1e4, int(i)%1e4)

然后：

print id_to_location('001200230004')
'/12/23/4/'

Answer 2

对于python 2.x，您有以下选项：

较新的str.format和完整的format specification的最佳选项，例如

"I like {food}".format(food="chocolate")

旧的interpolation formatting语法，例如

"I like %s" % "berries"
"I like %(food)s" % {"food": "cheese"}

string.Template，例如

string.Template('I like $food').substitute(food="spinach")

Answer 3

您希望对Python 3中的字符串使用format()方法：

http://docs.python.org/library/string.html#formatstrings

或者查看Python 2.X的字符串插值文档

http://docs.python.org/library/stdtypes.html