C#：将OpenFileDialog中的数据路径存储到变量中？

Question

在下面显示Windows.Forms.OpenFileDialog的c#类中，如何将数据路径存储到名为m_settings的变量中

private SomeKindOfData m_settings;
public void ShowSettingsGui()
{
    System.Windows.Forms.OpenFileDialog ofd = new System.Windows.Forms.OpenFileDialog();
    ofd.Multiselect = true;
    ofd.Filter = "Data Sources (*.ini)|*.ini*|All Files|*.*";
    if (ofd.ShowDialog() == DialogResult.OK)
    {
        string[] filePath = ofd.FileNames;
        string[] safeFilePath = ofd.SafeFileNames;
    }
        m_settings = //<-- ?
}

Answer 1

这应该能起到作用：

m_settings = ofd.FileName;

编辑:实际上，现在我不确定你是否想要文件夹路径。在这种情况下：

m_settings = Path.GetDirectoryName(ofd.FileName);