解析.srt文件

Question

1
00:00:00,074 --> 00:00:02,564
Previously on Breaking Bad...

2
00:00:02,663 --> 00:00:04,393
Words...

我需要用php解析srt文件，并用变量打印文件中的所有subs。

我找不到合适的注册表。在执行此操作时，我需要获取id、time和subtitle变量。在打印时，不一定要有array()等，必须打印与原始文件相同的内容。

我的意思是我必须像这样打印；

$number <br> (e.g. 1)
$time <br> (e.g. 00:00:00,074 --> 00:00:02,564)
$subtitle <br> (e.g. Previously on Breaking Bad...)

顺便说一句，我有这个代码。但它看不到线条。它必须被编辑，但是如何编辑呢？

$srt_file = file('test.srt',FILE_IGNORE_NEW_LINES);
$regex = "/^(\d)+ ([\d]+:[\d]+:[\d]+,[\d]+) --> ([\d]+:[\d]+:[\d]+,[\d]+) (\w.+)/";

foreach($srt_file as $srt){

    preg_match($regex,$srt,$srt_lines);

    print_r($srt_lines);
    echo '<br />';

}

Answer 1

下面是一个简短的状态机，用于逐行解析SRT文件：

define('SRT_STATE_SUBNUMBER', 0);
define('SRT_STATE_TIME',      1);
define('SRT_STATE_TEXT',      2);
define('SRT_STATE_BLANK',     3);

$lines   = file('test.srt');

$subs    = array();
$state   = SRT_STATE_SUBNUMBER;
$subNum  = 0;
$subText = '';
$subTime = '';

foreach($lines as $line) {
    switch($state) {
        case SRT_STATE_SUBNUMBER:
            $subNum = trim($line);
            $state  = SRT_STATE_TIME;
            break;

        case SRT_STATE_TIME:
            $subTime = trim($line);
            $state   = SRT_STATE_TEXT;
            break;

        case SRT_STATE_TEXT:
            if (trim($line) == '') {
                $sub = new stdClass;
                $sub->number = $subNum;
                list($sub->startTime, $sub->stopTime) = explode(' --> ', $subTime);
                $sub->text   = $subText;
                $subText     = '';
                $state       = SRT_STATE_SUBNUMBER;

                $subs[]      = $sub;
            } else {
                $subText .= $line;
            }
            break;
    }
}

if ($state == SRT_STATE_TEXT) {
    // if file was missing the trailing newlines, we'll be in this
    // state here.  Append the last read text and add the last sub.
    $sub->text = $subText;
    $subs[] = $sub;
}

print_r($subs);

结果：

Array
(
    [0] => stdClass Object
        (
            [number] => 1
            [stopTime] => 00:00:24,400
            [startTime] => 00:00:20,000
            [text] => Altocumulus clouds occur between six thousand
        )

    [1] => stdClass Object
        (
            [number] => 2
            [stopTime] => 00:00:27,800
            [startTime] => 00:00:24,600
            [text] => and twenty thousand feet above ground level.
        )

)

然后，您可以遍历subs数组或通过数组偏移量访问它们：

echo $subs[0]->number . ' says ' . $subs[0]->text . "\n";

要通过循环遍历并显示每个subs来显示所有subs，请执行以下操作：

foreach($subs as $sub) {
    echo $sub->number . ' begins at ' . $sub->startTime .
         ' and ends at ' . $sub->stopTime . '.  The text is: <br /><pre>' .
         $sub->text . "</pre><br />\n";
}

进一步阅读：SubRip Text File Format

Answer 2

这不会匹配，因为您的$srt_file数组可能如下所示：

Array
([0] => '1',
[1] => '00:00:00,074 --> 00:00:02,564',
[2] => 'Previously on Breaking Bad...'.
[3] => '',
[4] => '2',
...
)

您的正则表达式不会与这些元素中的任何一个匹配。

如果您打算将整个文件读入一个冗长的内存中，那么可以使用file_get_contents将整个文件内容读入一个字符串中。然后使用preg_match_all获取所有正则表达式匹配。

否则，您可能会尝试遍历数组，并尝试匹配各种正则表达式模式，以确定该行是id、时间范围还是文本，然后进行适当的操作。显然，您可能还需要一些逻辑来确保您以正确的顺序获取值(id，然后是时间范围，然后是文本)。

Answer 3

使用array_chunk()将file()数组分成4个块，然后省略最后一个条目，因为它是一个空行，如下所示：

foreach( array_chunk( file( 'test.srt'), 4) as $entry) {
    list( $number, $time, $subtitle) = $entry;
    echo $number . '<br />';
    echo $time . '<br />';
    echo $subtitle . '<br />';
}