我有以下查询,它的工作方式与我希望的一样,除了我想返回一个伪(?)每个属性所具有的从内部联接匹配的单元数计数的列。其中p.team = u.team和u.deleted = '0000-00-00 00:00:00‘和u.rates != '0’。我可以在同一个查询中这样做吗?
一个属性有几个单位。它们都连接到一个“团队”(比如用户名)。
SELECT DISTINCT p.title, p.state, p.city, p.regionID, p.team, p.type, p.lat, p.lng, p.url_title
FROM Properties AS p
INNER JOIN Units AS u ON p.team = u.team
INNER JOIN Rates AS r ON p.team = r.team
INNER JOIN Photos AS ph ON p.team = ph.team
AND p.public = '1'
AND u.rates != '0'
AND p.deleted = '0000-00-00 00:00:00'
AND u.deleted = '000-00-00 00:00:00'
AND r.deleted = '000-00-00 00:00:00'
AND ph.deleted = '000-00-00 00:00:00'
GROUP BY p.id
ORDER BY p.created ASC发布于 2012-07-20 02:18:34
由于您只有一个聚合,并且似乎是按Properties行进行分组,因此这应该是相对简单的。你的意思是像这样的东西(未经测试)?
SELECT p.title, p.state, p.city, p.regionID, p.team, p.type, p.lat, p.lng,
p.url_title , COUNT(u.*) AS number_of_units
FROM Properties AS p
INNER JOIN Units AS u ON p.team = u.team
INNER JOIN Rates AS r ON p.team = r.team
INNER JOIN Photos AS ph ON p.team = ph.team
AND p.public = '1'
AND u.rates != '0'
AND p.deleted = '0000-00-00 00:00:00'
AND u.deleted = '000-00-00 00:00:00'
AND r.deleted = '000-00-00 00:00:00'
AND ph.deleted = '000-00-00 00:00:00'
GROUP BY p.id, p.title, p.state, p.city, p.regionID, p.team, p.type, p.lat, p.lng, p.url_title
ORDER BY p.created ASC根据您的意思,您可能不得不改为使用COUNT(DISTINCT(u.id))。很难从你的问题中分辨出来。
作为参考,“硬方法”是创建一个子查询,以连接到该查询来进行计数。您可能需要执行此操作来计算多个不相关的项目,或者按一个项目分组并按另一个项目计数:
SELECT DISTINCT p.title, p.state, p.city, p.regionID, p.team, p.type, p.lat, p.lng,
p.url_title, uuCount.number_of_units
FROM Properties AS p
INNER JOIN Units AS u ON p.team = u.team
INNER JOIN Rates AS r ON p.team = r.team
INNER JOIN Photos AS ph ON p.team = ph.team
AND p.public = '1'
AND u.rates != '0'
AND p.deleted = '0000-00-00 00:00:00'
AND u.deleted = '000-00-00 00:00:00'
AND r.deleted = '000-00-00 00:00:00'
AND ph.deleted = '000-00-00 00:00:00'
INNER JOIN
(
SELECT uu.team, COUNT(*) AS number_of_units
FROM Units uu
WHERE uu.deleted = '0000-00-00 00:00:00'
AND u.rates != '0'
GROUP BY uu.team
) AS uuCount ON p.team = uuCount.team
GROUP BY p.id
ORDER BY p.created ASChttps://stackoverflow.com/questions/11566893
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