我用以下代码创建了一个视图
SELECT
CONVERT(NVARCHAR, YEAR(okuma_tarihi)) + 'T1' AS sno,
YEAR(okuma_tarihi) AS Yillar,
SUM(toplam_kullanim_T1) AS TotalUsageValue, 'T1' AS UsageType
FROM
TblSayacOkumalari
GROUP BY
CONVERT(NVARCHAR, YEAR(okuma_tarihi)) + 'T1', YEAR(okuma_tarihi)
UNION ALL
SELECT
CONVERT(NVARCHAR, YEAR(okuma_tarihi)) + 'T2' AS sno,
YEAR(okuma_tarihi) AS Yillar,
SUM(toplam_kullanim_T2) AS TotalUsageValue, 'T2' AS UsageType
FROM
TblSayacOkumalari
GROUP BY
CONVERT(NVARCHAR, YEAR(okuma_tarihi)) + 'T1', YEAR(okuma_tarihi)
UNION ALL
SELECT
CONVERT(NVARCHAR, YEAR(okuma_tarihi)) + 'T3' AS sno,
YEAR(okuma_tarihi) AS Yillar,
SUM(toplam_kullanim_T3) AS TotalUsageValue, 'T3' AS UsageType
FROM
TblSayacOkumalari
GROUP BY
CONVERT(NVARCHAR, YEAR(okuma_tarihi)) + 'T1', YEAR(okuma_tarihi)我想将CONVERT(nvarchar, YEAR(okuma_tarihi)) + 'T1' AS sno定义为主键,这可能吗?如果这是可能的,我该怎么办?
发布于 2012-07-12 01:55:30
不能在视图上创建主键。在SQL Server中,您可以使用create an on a view,但这与创建主键不同。
如果你给我们更多的信息,为什么你想在你的视图上有一个键,也许我们可以帮助你。
发布于 2017-03-31 11:50:29
您可能无法创建主键(每次),但如果您的视图基于具有主键的表,并且该键包含在视图中,则主键也将反映在视图中。需要主键的应用程序可以接受视图,就像Lightswitch一样。
发布于 2020-02-11 22:55:53
参加这个聚会有点晚了--但这也很有效:
CREATE VIEW [ABC].[View_SomeDataUniqueKey]
AS
SELECT
CAST(CONCAT(CAST([ID] AS VARCHAR(4)),
CAST(ROW_NUMBER() OVER(ORDER BY [ID] ASC) as VARCHAR(4))
) AS int) AS [UniqueId]
,[ID]
FROM SOME_TABLE JOIN SOME_OTHER_TABLE
GO在我的例子中,连接的结果是ID -主键被重复5次(关联不同的唯一数据),其中的妙招是可以从每个UniqueID有效地确定原始ID ID+RowNumber() = 11,12,13,14,21,22,23,24等等。如果您将RowNumber()和ID添加回视图中,您可以很容易地从数据中确定您的原始键。但是-这不是应该提交到表中的东西,因为我相当确定视图的RowNumber()永远不会随着底层数据的改变而可靠地相同,即使使用OVER(ORDER BY ID ASC)来尝试和帮助它。
示例输出(从REF.View_Systems中选择UniqueId,ID,ROWNR,Name ):
UniqueId ID ROWNR Name 11 1 1 Amazon A 12 1 2 Amazon B 13 1 3 Amazon C 14 1 4 Amazon D 15 1 5 Amazon E
Table1:
[ID] [Name] 1 Amazon
Table2:
[ID] [Version] 1 A 1 B 1 C 1 D 1 E
CREATE VIEW [REF].[View_Systems]
AS
SELECT
CAST(CONCAT(CAST(TABA.[ID] AS VARCHAR(4)),
CAST(ROW_NUMBER() OVER(ORDER BY TABA.[ID] ASC) as VARCHAR(4))
) AS int) AS [UniqueId]
,TABA.[ID]
,ROW_NUMBER() OVER(ORDER BY TABA.[ID] ASC) AS ROWNR
,TABA.[Name]
FROM [Ref].[Table1] TABA LEFT JOIN [Ref].[Table2] TABB ON TABA.[ID] = TABB.[ID]
GOhttps://stackoverflow.com/questions/11438319
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