我正在尝试使用applescript来检索歌曲的BPM值。最终,我想用游戏来实现它。下面是我的代码:
import os
import time
import sys
def getBPM():
iTunesInstruct = """'
tell application "iTunes"
set k to get bpm of current track
end tell
return k
'"""
bpm = os.system('arch -i386 osascript -e ' + iTunesInstruct )
#bpm =90
bpm = int(bpm)
bpm = round(bpm)
if bpm > 250:
bpm = 200
return bpm
def getBeatSecond(bpm):
bps = float(bpm) / 60
#raw_input(bps)
return float(bps)
i = 0
beatMatch = True
while True:
beat = 1 / getBeatSecond(getBPM()) # BPS Beat divided by a second.
if beatMatch:
time.sleep(beat)
print beat
else:
raw_input('Go??')
i += 1
if i > 50:
break但这似乎只有效一次...它得到了我正在听的歌曲的BPM,看到它是94,然后似乎在第二次迭代时它认为它是0,然后除以0,然后就死了。到底怎么回事?
发布于 2012-07-09 08:26:06
os.system不等待命令完成。
90 =是osascript的结果, =无错误,是退出状态(os.system)。
使用subprocess.Popen
from subprocess import Popen, PIPE
def getBPM():
cmd = "arch -i386 osascript -e " + """'tell application "iTunes" to return bpm of current track'"""
bpm, tError = Popen(cmd, shell=True, stdin=PIPE, stdout=PIPE, stderr=PIPE).communicate()
if bpm > 250:
return = 200
return int(bpm)https://stackoverflow.com/questions/11386230
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