我正在尝试解析一个格式如下的文件:
BEGIN:VEVENT
CREATED:20120504T163940Z
DTEND;TZID=America/Chicago:20120504T130000
DTSTAMP:20120504T164000Z
DTSTART;TZID=America/Chicago:20120504T120000
LAST-MODIFIED:20120504T163940Z
SEQUENCE:0
SUMMARY:Test 1
TRANSP:OPAQUE
UID:21F61281-FB76-467F-A2CC-A666688BD9B5
X-RADICALE-NAME:21F61281-FB76-467F-A2CC-A666688BD9B5.ics
END:VEVENT我需要获取每一行中冒号或分号后面的值,并将它们放入一个对象的属性中。我正在尝试使用Regex来做这件事,但在我使用它之后(可能一年两次),我基本上忘记了我所知道的所有关于Regex的事情。任何帮助都将不胜感激。
发布于 2012-06-15 02:08:44
用几个例子运行它,看看它是否能实现您想要的效果。我得到了关于拆分或IndexOf的其他评论,但如果您希望分隔符是冒号或分号,那么正则表达式可能更好。
string line = "LAST-MODIFIED:20120504T163940Z";
var p = Regex.Match(line, "(.*)?(:|;)(.*)$", RegexOptions.CultureInvariant | RegexOptions.IgnoreCase | RegexOptions.Singleline);
Console.WriteLine(p.Groups[0].Value);
Console.WriteLine(p.Groups[1].Value);
Console.WriteLine(p.Groups[2].Value);
Console.WriteLine(p.Groups[3].Value);发布于 2012-06-15 03:33:29
编辑
这篇文章让我开始思考iCal格式。
在昨天之前,我不知道iCal格式是什么。但是,在阅读了1998年的规范之后,很明显,这个页面上的答案都不足以解析内容。而且,它真的太复杂了,即使对于我下面的一般正则表达式也是如此。
考虑到这一点,这里有一个解决方案,它只解析行内容,就像从通用行内容解析规范中收集的那样。这是朝着正确方向迈出的一步,希望有人能从中受益。它不做行续行,也不进行验证。
C#代码
Regex iCalMainRx = new Regex(
@" ^ (?<name> [^[:cntrl:]"";:,\n]+ )
(?<parameter>
;
(?<param_name> [^[:cntrl:]"";:,\n]+ )
=
(?<param_value>
(?: (?:[^\S\n]|[^[:cntrl:]"";:,])* | "" (?:[^\S\n]|[^[:cntrl:]""])* "" )
(?: , (?: (?:[^\S\n]|[^[:cntrl:]"";:,])* | "" (?:[^\S\n]|[^[:cntrl:]""])* "" ) )*
)
)*
:
(?<value> (?:[^\S\n]|[^[:cntrl:]])* )
$ ", RegexOptions.IgnorePatternWhitespace);
Regex iCalPvalRx = new Regex(
@" ^ (?<pvals> (?:[^\S\n]|[^[:cntrl:]"";:,])* | "" (?:[^\S\n]|[^[:cntrl:]""])* "" )
(?: ,+ (?<pvals> (?:[^\S\n]|[^[:cntrl:]"";:,])* | "" (?:[^\S\n]|[^[:cntrl:]""])* "" ) )*
$ ", RegexOptions.IgnorePatternWhitespace);
string[] lines = {
"BEGIN:VEVENT",
"CREATED:20120504T163940Z",
"DTEND;TZID=America/Chicago:20120504T130000",
"DTSTAMP:20120504T164000Z",
"DTSTART;TZID=,,,America/Chicago;Next=;last=\"this:;;;:=\";final=:20120504T120000",
"LAST-MODIFIED:20120504T163940Z",
"SEQUENCE:0",
"SUMMARY:Test 1",
"TRANSP:OPAQUE",
"UID:21F61281-FB76-467F-A2CC-A666688BD9B5",
"X-RADICALE-NAME:21F61281-FB76-467F-A2CC-A666688BD9B5.ics",
"END:VEVENT",
};
foreach (string str in lines)
{
Match m_content = iCalMainRx.Match( str );
if (m_content.Success)
{
Console.WriteLine("Key = " + m_content.Groups["name"].Value);
Console.WriteLine("Value = " + m_content.Groups["value"].Value);
CaptureCollection cc_pname = m_content.Groups["param_name"].Captures;
CaptureCollection cc_pvalue = m_content.Groups["param_value"].Captures;
if (cc_pname.Count > 0)
{
Console.WriteLine("Parameters: ");
for (int i = 0; i < cc_pname.Count; i++)
{
// Console.WriteLine("\t'" + cc_pname[i].Value + "' = '" + cc_pvalue[i].Value + "'");
Console.WriteLine("\t'" + cc_pname[i].Value + "' =");
Match m_vals = iCalPvalRx.Match( cc_pvalue[i].Value );
if (m_vals.Success)
{
CaptureCollection cc_vals = m_vals.Groups["pvals"].Captures;
for (int j = 0; j < cc_vals.Count; j++)
{
Console.WriteLine("\t\t'" + cc_vals[j].Value + "'");
}
}
}
}
Console.WriteLine("-------------------------");
}
}输出
Key = BEGIN
Value = VEVENT
-------------------------
Key = CREATED
Value = 20120504T163940Z
-------------------------
Key = DTEND
Value = 20120504T130000
Parameters:
'TZID' =
'America/Chicago'
-------------------------
Key = DTSTAMP
Value = 20120504T164000Z
-------------------------
Key = DTSTART
Value = 20120504T120000
Parameters:
'TZID' =
''
'America/Chicago'
'Next' =
''
'last' =
'"this:;;;:="'
'final' =
''
-------------------------
Key = LAST-MODIFIED
Value = 20120504T163940Z
-------------------------
Key = SEQUENCE
Value = 0
-------------------------
Key = SUMMARY
Value = Test 1
-------------------------
Key = TRANSP
Value = OPAQUE
-------------------------
Key = UID
Value = 21F61281-FB76-467F-A2CC-A666688BD9B5
-------------------------
Key = X-RADICALE-NAME
Value = 21F61281-FB76-467F-A2CC-A666688BD9B5.ics
-------------------------
Key = END
Value = VEVENT
-------------------------发布于 2012-06-15 02:03:57
对于简单的ICAL文件而不是RegEx,插入行并使用IndexOf(":")就足够了。
检查是否已经存在ICAL解析器和related questions ical+C#。
https://stackoverflow.com/questions/11038703
复制相似问题