如何在xmpphp中接收消息

Question

在示例中清楚地说明了如何发送消息，但我不清楚如何接收服务器中其他客户端发起的消息任何帮助都是非常感谢的

下面是我发送消息的代码

include("xmpphp/xmpp.php");

//username = user without domain, "user" and not "user@server" - home is the resource
$conn = new XMPPHP_XMPP('localhost', 5222, 'robel27', 'yoyene122127', 'kiyos');
// Enables TLS - enabled by default, call before connect()!
$conn->useEncryption(false);

$conn->connect();
 // shows the user's status message
$conn->presence();
$conn->processUntil(array('session_start', 'roster_received'));
$conn->processTime(2);
$conn->message('kiyos12@kiyos', $_POST['msg1']);
$conn->disconnect();

Answer 1

要获取消息，可以使用$data = $conn->processUntil('message');